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Semaphore
- 通过编程6个哲学家吃饭了解进程(线程)同步与死锁.
asd
- 哲学家吃饭问题 直到就自己下吧,大学很多学校要用的,不用客气!
eating
- 模拟哲学家进餐的同步问题,实现一个既没有两邻座同时吃饭,又没有人饿死(永远拿不到一双筷子)的算法
zhexuejia
- 哲学家进餐问题实现-dining philosophers problem of achieving
3281411350
- 哲学家吃饭问题解决-philosopher food problem solving
vc_semaphore
- 自己写的。用信号量机制来解决哲学家问题中的死锁。附有详细注解。-wrote it myself. Using signal volume philosopher mechanism to solve the problem of deadlock. Accompanied by a detailed explanation.
哲学家问题0
- 先用BACC编译,再用BAINTERP运行-using the BACC compiler, and then run BAINTERP
philosphi
- 操作系统线程哲学家就餐算法原代码-operating system threads the dining philosophers algorithm source code
DiningPhilosophor1
- 哲学家进餐问题,课程设计,界面友好,实现功能很好。模拟了同步互斥
philosophy-five-jcsp
- 升级版本,五个哲学家问题,用jcsp 实现。
philosopher
- 哲学家就餐问题,一共七个哲学家,无限循环。结束进程才能停止程序
philo
- 用pthread实现哲学家问题,利用信号量实现同步。
zhexuejia
- linux用多线程同步方法解决哲学家就餐问题(Dining-Philosophers Problem)
philosopher
- 经典的哲学家就餐问题的C语言版本
eat
- 哲学家进餐问题Java版-dining philosophers problem Java version
哲学家进餐问题
- linux进程间通信,父进程,子进程的创建-inter-process communication, parent process, the process of creating son
PhilospherDining
- 它是一个经典的算法-哲学家进餐问题,用VC++实现,通过它大家可以掌握Windows中的多线程编程-It is a classic algorithm-the Dining Philosophers, VC + +, through which we can grasp the Windows multi-threaded programming
乳猪
- 一个多线程同步问题. 哲学家进餐问题!! java实现-a multithreaded synchronization. Dining Philosophers problem! ! Java Implementation
Rousseau1
- 五个哲学家,它们的生活方式是交替地进行思考和进餐。哲学家们共用一张圆桌,分别坐在周围的五张椅子上。在圆桌上有五个碗和五支筷子,平时一个哲学家进行思考,饥饿时便试图取用左、右最靠近他的筷子,只有在他拿到两支筷子时才能进餐,进餐毕,放下筷子又继续思考。-five philosophers, their lify style is alternately thinking and eating. philosophers share common table ,and sitting on five