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SquareRoot_Submit
- This a square root unit of several floating point sizes in VHDL.-This is a square root unit of several floating point sizes in VHDL.
fast_antilog_latest.tar
- Anti-Logarithm (square-root), base-2, single-cycle
Learning
- Multilayer perceptron learns to get square root.
sq_root
- program to find square root of a number
testrc
- 套用公式 计算电阻电容的值 I1 = U / R + j2πfCU I2 = U / R + Kj2πfCU IR = U / R = ((K^2 *I1^2-I2^2)/(K^2-1))开根号 C=(I2-I1)/(4Pi*U)-Apply the formula to calculate the value of resistance and capacitance I1 = U/R+ j2πfCU I2 = U/R+ Kj2πfCU IR = U/R =
shuzhifenxi
- 里面是例题,Gauss消元法,Gauss列主元消元法,平方根法,追赶法,SOR法求方程组的根-There are examples, Gauss elimination method, Gauss elimination method pivot column, the square root law, pursuit method, SOR Method root equations
jisuanqi
- VC实现的简单计算器,可进行加减乘除、开平方等运算-VC to achieve a simple calculator for addition, subtraction, square root and other operations
proj1_1
- 求小于等于n 的所有的素数,算法时间复杂度为O(根号下n)-Less than or equal n, find all the prime numbers, the algorithm time complexity is O (square root of the next n)
MyCalculator
- 运算器,包含加减乘除四则基本运算,平方,开方等-Arithmetic unit, including the four basic operations of addition, subtraction, square, square root, etc.
rmse
- compute the root-mean-square error
jisuanqi
- 利用C++语言编写的计算器,实现了计算加减乘除开方求模的功能。-C++ language using the calculator, the calculation formula can be used to achieve square root modulo function.
LDL
- 计算方法中的LDL分解。平方根分解。用VB编程。分解实对称矩阵-Calculation of LDL decomposition. Square Root. With VB programming. Decomposition of real symmetric matrices
jsq
- Delphi简单计算器,三角函数,平方,开方-Delphi simple calculator, trigonometric functions, square, square root
PiCalculator
- 这个算法是平方收敛的(每次迭代有效位数增加一倍), 这样要求到Q位有效数字,就至少要log2Q+1次迭代 显然,这种计算是要高精度表示的, 我所用的算法就是普通的高精度加减乘除 加减是O(n)的,时间花费很少。 乘除是O(n2)的,主要的时间花费都在这上面。 而由这个算法中可以看到,bn的计算需要开根号。 这里有两种开根号的办法: ①用初中教我们的方法,每次开两位根号,用除法减掉, 这样所需时间为n2·n/2=O(n3),不可忍受! ②用牛顿迭
Calculater
- 我编写的一个简易计算器。实现基本运算、乘方开方等功能。-I wrote a simple calculator. For basic computing, power and square root functions.
Inc
- 采用牛顿迭代法求平方根,直接向上取整,获得相应的值-Newton Iterative Method for the rounded square root
LECalculator
- 3.1 线性方程组类设计 3.2 全选主元高斯消去法 3.3 全选主元高斯-约当消去法 3.4 复系数方程组的全选主元高斯消去法 3.5 复系数方程组的全选主元高斯-约当消去法 3.6 求解三对角线方程组的追赶法 3.7 一般带型方程组的求解 3.8 求解对称方程组的分解法 3.9 求解对称正定方程组的平方根法 3.10 求解大型稀疏方程组的全选主元高斯-约当消去法 3.11 求解托伯利兹方程组的列文逊方法 3.12 高斯-赛德尔
num.cpp
- 数论mod有关算法 丢翻图方程 线性同余方程解 原始根 gcd exgcd 中国剩余定理 需要高精度库gmpc-gcd exgcd diophantic equation linear congruence Chinese reminder square root primitive root
Calculator
- 简单计算器的Java实现,含有+、-、*、/,取余,求倒数,求平方根功能-Simple calculator Java implementations, containing+,-,*, /, take over, I pray, let the square root function countdown
gaijin
- 这个程序是用改进平方根法对线性方程组进行求解,要求系数矩阵必须是对称正定矩阵-This procedure is used to improve the square root method to solve linear equations, requiring the coefficient matrix must be symmetric positive definite matrix