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  1. bianyi

    0下载:
  2. 汇编原理课设:主要有词法分析,语法分析,语义分析- A program to perform Euclid s Algorithm to compute gcd.
  3. 所属分类:Compiler program

    • 发布日期:2017-04-03
    • 文件大小:8993
    • 提供者:yun
  1. RSA

    1下载:
  2. RSA算法实验报告和代码 1.选取两个素数p,q(不可相差悬殊) 2.计算n=pq,f(n)=(p-1)(q-1) 3.选取e,满足1<e<f(n),则gcd(e,f(n))=1 4.计算d,满足de=1 mod f(n)。一般d>=[n的四分之一方],(e,n)为公钥,(p,q,d)为私钥,将明文0,1序列分组,使每组十进制小于n。c=[m的e次方] mod n,m=[c的d次方] mod n。-RSA algorithm and code an experi
  3. 所属分类:Crypt_Decrypt algrithms

    • 发布日期:2017-03-24
    • 文件大小:82096
    • 提供者:jhp627
  1. prolog

    0下载:
  2. 用Prolog写的一些基本函数,如compress, decompress, pack, gcd, duplicate, sort-Some fundamental functions written in Prolog, such as compress, decompress, pack, gcd, duplicate, sort.
  3. 所属分类:Data structs

    • 发布日期:2017-04-04
    • 文件大小:2032
    • 提供者:David
  1. gcd

    0下载:
  2. oujilide suanfa de kuozhansuanfade shxiamzj jdsa lfjdas f-Euclid suandafa a ldjfdkuodahznadnfa,dfna dsfjdas fjdas
  3. 所属分类:Crypt_Decrypt algrithms

    • 发布日期:2017-04-10
    • 文件大小:1188979
    • 提供者:li
  1. mimaxue

    0下载:
  2. 内含背包程序,RSA程序,中国剩余定理程序和GCD程序的源代码-Includes backpack program, RSA program, Chinese remainder theorem programs and GCD program' s source code
  3. 所属分类:CA program

    • 发布日期:2017-03-31
    • 文件大小:2153
    • 提供者:jack
  1. a10

    0下载:
  2. basic java program which can calculate the gcd of two integer -basic java program which can calculate the gcd of two integer ...
  3. 所属分类:Java Develop

    • 发布日期:2017-04-10
    • 文件大小:1071
    • 提供者:yugioh
  1. gcd2

    0下载:
  2. euclids algorithm that takes the gcd and converts it to find the largest and smallest gcd
  3. 所属分类:software engineering

    • 发布日期:2017-03-26
    • 文件大小:702
    • 提供者:kpalakode
  1. Shell_Scripting

    0下载:
  2. Sample programs of shell scr ipting. finding the maximum no. finding the gcd of a no. etc.
  3. 所属分类:Linux-Unix program

    • 发布日期:2017-04-05
    • 文件大小:32628
    • 提供者:vivek.N.K.
  1. gcd

    0下载:
  2. AntNet :Routing in Communication Networks -AntNet :Routing in Communication Networks
  3. 所属分类:Linux Network

    • 发布日期:2017-04-09
    • 文件大小:558
    • 提供者:sap
  1. VHDLcodes

    0下载:
  2. Behavioral descr iption of ALU, RAM MODULE, ROM MODULE, DIVIDE BY N COUNTER, GENERIC DIVIDER 2n+1, GCD CALCULATOR, GCD FSM CODE, JK FLIP FLOP in VHDL . These are fully synthesized codes with optimization.- Behavioral descr iption of ALU, RAM MODULE,
  3. 所属分类:VHDL-FPGA-Verilog

    • 发布日期:2017-03-28
    • 文件大小:6163
    • 提供者:Vijay
  1. gcd

    0下载:
  2. greatest common divisor c-greatest common divisor c++
  3. 所属分类:Other systems

    • 发布日期:2017-04-15
    • 文件大小:6331
    • 提供者:islam
  1. Desktop

    0下载:
  2. 求两个数的最大公约数gcd()和仿射加密解密的c++算法- Asks two numbers the greatest common divisor gcd() c++ algorithm
  3. 所属分类:Other systems

    • 发布日期:2017-04-02
    • 文件大小:985
    • 提供者:刘文杰
  1. hi-precision

    0下载:
  2. 实现大数操作的算法模板,重载了基本操作(+,-,* ,/),取模,次方,gcd等-Operation of the algorithm to achieve large numbers templates, overloads the basic operation (+,-,*, /), modulus, power, gcd, etc.
  3. 所属分类:Data structs

    • 发布日期:2017-04-08
    • 文件大小:3024
    • 提供者:夏治文
  1. gcd_lcm

    0下载:
  2. 给出两整数a与b, 找出a与b的最小公倍数LCM(a,b), 找出a与b的最大公因子GCD(a,b).-finds the LCM(Lowest Common Multiple)/GCD(Greatest Common Divisor) of two positive integers
  3. 所属分类:Algorithm

    • 发布日期:2017-04-08
    • 文件大小:539
    • 提供者:jason..
  1. power shell

    1下载:
  2. A Sample program on Microsoft Powershell. It have functions of Mathematical functions such as GCD,
  3. 所属分类:Shell编程

  1. Fraction

    0下载:
  2. Develop a Fraction class that is capable of doing arithmetic with fractions. * Fractions are held in lowest terms, with the gcd() method. * Use a toString() method to format the result.-Develop a Fraction class that is capable of doing arithm
  3. 所属分类:Java Develop

    • 发布日期:2017-03-26
    • 文件大小:861
    • 提供者:LeiShi
  1. VHDLvsVerilog

    0下载:
  2. This document is in two parts. The first part takes an unbiased view of VHDL and Verilog by comparing their similarities and contrasting their differences. The second part contains a worked example of a model that computes the Greatest Common Divisor
  3. 所属分类:VHDL-FPGA-Verilog

    • 发布日期:2017-03-29
    • 文件大小:24621
    • 提供者:lavanya
  1. GCD

    0下载:
  2. 用VC++ 开发AutoCAD的一个简单的示例代码-a simple sample of VC++ developing autoCAD
  3. 所属分类:Graph Drawing

    • 发布日期:2017-03-31
    • 文件大小:67108
    • 提供者:dmliu
  1. GCD

    0下载:
  2. Help to find the Greatest Common Divisor of Numbers
  3. 所属分类:Console

    • 发布日期:2017-04-10
    • 文件大小:755
    • 提供者:pixel
  1. gcd_lcm

    0下载:
  2. 求两个100以内整数的最大公约数和最小公倍数,只用加法和减法运算-Find the greatest common divisor of two integers less than 100 and the least common multiple, only addition and subtraction
  3. 所属分类:VHDL-FPGA-Verilog

    • 发布日期:2017-03-27
    • 文件大小:847
    • 提供者:刘涛
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