搜索资源列表
ac1000-1199
- POJ上1000-1199,除1070,1109,1115,1138,1139,1162,1172,1181的所有代码-POJ s codes. 1000-1199, except:1070,1109,1115,1138,1139,1162,1172,1181
JungleRoads1251
- 北大 poj 上 题目:JungleRoads1251的解题源码-JungleRoads1251 answer
code
- vs2013下的工程文档,是poj昂贵的聘礼的源码,需要的朋友可以下载-engineering documentation vs2013 under poj expensive dowry is the source, a friend in need can be downloaded
LostCows
- POJ 2182 引自余立功《算法训练教程》,线段树的应用-POJ 2182 segment tree
Mayors-posters
- POJ 2528 引自余立功《算法训练教程》,线段树的应用-POJ 2528 segment tree
2876
- code of problem from http://poj.org/ No.2876
1001
- acm北大测试平台1001题幂的高精度计算的代码,检测通过。-this is the code for the question 1001 of Peking university poj stage
Flip-Game
- POJ 755——Flip Game 有一块4*4的棋盘,每个格子上有一个黑色或白色的棋子,翻转一个棋子会使这个棋子及周围的4个棋子变为相反的颜色,给定棋盘的初始状态,求将棋盘中的格子都变为黑色或白色的最少翻转次数。-POJ 755- Flip Game has a 4* 4 chessboard, each grid on a black or white piece, flip a pawn makes this piece and around 4 pawn becomes the opp
POJ-2385
- 有左右两种选择,状态就是在这两条线转来转去-dynamic programming
poj-3070-Fibonacci
- fibonacci 很好的ACM代码 快点下载吧-fibonacci 很好的ACM代码 快点下载吧!!!!!!!!!!!!!!!
Flip-Game
- POJ 755——Flip Game 有一块4*4的棋盘,每个格子上有一个黑色或白色的棋子,翻转一个棋子会使这个棋子及周围的4个棋子变为相反的颜色,给定棋盘的初始状态,求将棋盘中的格子都变为黑色或白色的最少翻转次数。-POJ 755- Flip Game has a 4* 4 chessboard, each grid on a black or white piece, flip a pawn makes this piece and around 4 pawn becomes the opp
wow
- 北京大学POJ 百练问题3750:魔兽世界源代码-Peking University, 3750 POJ hundred training issues: the source code for World of Warcraft ~ ~ ~
Communication-System
- 北大 POJ 1018 communication system-POJ 1018 communication system
acm_code
- 这是本科暑假联系ACM的代码,有的是北大OJ的,有的是杭电OJ的。分为并查集,动态规划,高精度,树形,线段树五个部分-This files have many acm codes. Users can look at the problems at POJ or HangDian OJ.
1298
- poj 1298 源代码! 直接运行即可!-poj 1298
cPP
- 关于二部图、线段数、树状数组、树的分治的一些POJ题目的解答-About two figure, the number of segments, Fenwick tree, the tree of divide and conquer some POJ topic answers
ACM_in_POJ
- POJ中的100多道题的源码,供大家参考,想要的更多的可以联系~-100 codes in POJ,welocme programers contect with me~
APB_Problem
- POJ试题 A+B Q: Where are the input and the output? A: Your program shall always read input stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use scanf in C or cin in C++ to read stdin, and use printf in C
POJ1915_bfs
- poj1915双向bfs.-poj 1915
poj3268(SPFA)
- poj 3268 ac代码-ac code spfa