搜索资源列表
sin-fft
- 注释非常详细的FFT变换,用matlab实现两个正弦函数的区分,初学着都能看懂-Notes very detailed FFT transform, with the achievement of the two sine function matlab distinction, the novice can understand
adctest_maxim0911
- 通用高速ADC动态性能测试MATLAB code,包括SNR,SINAD,ENOB,THD,SFDR,并绘制频域幅值曲线-MATLAB code for high speed ADC dynamic specific tests, including SNR, SINAD, ENOB,THD,SFDR,and so on.
fft
- Radix-2 Fast Fourier Transform, real or complex sin/cos transform -Radix-2 Fast Fourier Transform, real or complex sin/cos transform
FFTanalyser
- sample FFT Analyser using matlab. using cos and sin function.
fft
- Matlab程序,GUI窗口 用FFT程序计算有限长度正弦信号y=sin(2*pi*f*t) ,0<=t<=N*T-FFT program calculate the finite length of the sinusoidal signal y = sin (2* pi* f* t), 0 < = t < = N* T respectively the DFT results obtained and analyzed and discussed in the fol
sin-FFT--IFFT
- 对原始正弦信号进行傅里叶变换与逆变换并给出结果-Fourier transform and inverse transform the original sinusoidal signals and gives results
ee
- 快速傅里叶变换 (FFT) 实现,给定信号x(t)=sin(2πf0t),f0=50Hz,对x(t)以fs=200Hz进行抽样,抽样点数为N=16。编写程序实现对x(n)的快速傅里叶变换,求得相应的X(K)。-Fast Fourier Transform (FFT) to achieve a given signal x (t) = sin (2πf0t), f0 = 50Hz, for x (t) with fs = 200Hz sampling, the sampling points is
SIN
- 正弦波的产生方法,以及fft频谱画图,初学者学习-The method of generating a sine wave, and the drawing fft spectrum
fft1-in-matlab
- FFT 实例 x=0.5*sin(2*pi*15*t)+2*sin(2*pi*40*t)。采样频率fs=100Hz,分别绘制N=128、1024点幅频图-FFT in Matlab example
fft2-in-matlab
- FFT应用举例 x=0.5*sin(2*pi*15*t)+2*sin(2*pi*40*t),fs=100Hz,绘制: (1)数据个数N=32,FFT所用的采样点数NFFT=32; (2)N=32,NFFT=128; (3)N=136,NFFT=128; (4)N=136,NFFT=512。-FFT in matlab example
FFT
- 1.x=0.5*sin(2*pi*15*t)+2*sin(2*pi*40*t)。采样频率fs=100Hz,分别绘制N=128、1024点幅频图。 2.x=0.5*sin(2*pi*15*t)+2*sin(2*pi*40*t),fs=100Hz,绘制: (1)数据个数N=32,FFT所用的采样点数NFFT=32; (2)N=32,NFFT=128; (3)N=136,NFFT=128; (4)N=136,NFFT=512。-1. X = 0.5* sin (2* PI* 15*
fft-computing-sin-cos-FIG.
- fft计算sin_cos图,有代码和仿真效果图,体验fft和频谱特性-fft calculation sin_cos graph, code and simulation renderings, experience fft and spectral characteristics