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tianxiang-Qu
- 该实验室的目标是实现一个排序算法排序CD专辑数组中的对象。您将创建一个结构化的方法来划分的程序和算法的逻辑结构的应用程序。-The goal of the lab is to implement a sorting algorithm for sorting CD album objects in an array. You will create a structured application using methods to divide the program and algorithm
IntegerMultiply
- 算法分析与设计 用递归分治算法解决大整数乘积问题（java源码）-Algorithm Analysis and Design Recursive divide and conquer algorithm to solve the problem of large integer multiplication. (Java source code)
java
- 用的分治法的思想,凸包顶点正好可以构成循环,感觉比较新颖,就是不断顺时针旋转,按照书上那个公式不断找出左边的点和顶点,不断存入到数组中,最后的输出刚好是顺时针的输出,创建了好几个数组,其中还有一个三维数组,用法比较特殊,无意间想到的-Ideological divide and conquer, the convex hull of the vertices can just constitute a cycle, feeling relatively new, is constantly r
Birds
- 经典的java网络编程样例，提供了多种设计模式的应用：工厂、模板，最重要的是如何划分每个类的职责，对广大java开发者是一份很好的参考资料-The classic java network programming sample, provides variety of design patterns: factory template, the most important thing is how to divide the responsibilities of each class, th
JSP-Calculator
- JSP版的网络计算器，体现书写JSP文件的完整框架，并实现加、减、乘、除的基本运算功能。-A calculator written using JSP, which includes JSP labels, Javascr ipt, HTML and Java grammar. It shows hows to "add, subtract, multiply and divide .
calc
- 用javaSwing插件完成的简单的计算器，完成基本的加、减、乘、除、小数点功能。-Simple calculator with completion of the javaSwing plug to complete the basic add, subtract, multiply, divide, decimal point function.
ArithmeticTest
- 图形界面的算数练习器，可自己选择加减乘除，多位运算，定时，最后统计分数。-a graph ArithmeticTest ，you can choose the plus minus multiply divide. set time to do it . the program willgive a grade to you
KMEANS
- 输入：聚类个数k，以及包含 n个数据对象的数据库。输出：满足方差最小标准的k个聚类。处理流程： （1）从 n个数据对象任意选择 k 个对象作为初始聚类中心. （2）根据每个聚类对象的均值（中心对象），计算每个对象与这些中心对象的距离；并根据最小距离重新对相应对象进行划分；（3）重新计算每个（有变化）聚类的均值（中心对象） （4）循环（2）到（3）直到每个聚类不再发生变化为止-Input: number of clusters k, and n data object contains a
MvcCms
- MvcCms架构分析(底层框架分离)源码 MvcCms该项目是系Orachrd Oxite 一系列MVC3应用比较成熟的产品之一，开发都是以微软开发模式“分而治之”为基础。 涉及到的技术； 1.MVC3 2.CastleWindsor 3.ServiceLocator 4.多UI， 5.MemberProvider 6.Cache(在该项目中Cache的应用也是一个很好的实例，重点在于Cache与动态信息结合的使用。以及Cache自动更新。） 关于Castle
Calculators
- 计算器的设计与实现 设计一个能实现计算器功能的Java程序，可以进行加、减、乘、除（另外可适当加上阶乘、正弦、余弦和指数）运算。-Design and Implementation of the calculator design a Java program that implements a calculator function, you can add, subtract, multiply, and divide (may be appropriate to add anot
grid
- 分治算法的直观应用，有GUI。即在8*8的格子中放一块障碍，求一种分配方案使得能用相同的直角方块（共3块成L字形）铺满整个方格。-Divide and conquer algorithm intuitive applications, there GUI. Ie 8* 8 grid put an obstacle, seeking an allocation scheme makes possible the same rectangular box (a total of three L-sh
wjhlgsspxt[v20100720]
- 1. 添加审批：可自由选择审批流程。 2. 待办审批：查看根据用户权限/身份划分。 3. 编辑审批：编辑根据用户权限与审批所属状态划分。 4. 审批查询：强大的审批查询引擎，可对任何查询错误给出提示。 5. 管理审批：管理员可对审批进行审批进度调整。 6. 用户管理：可对用户类别、部门、权限等划分。 -1 Add approval: the freedom to choose the approval process. (2) pending approva
SUANFAclass
- 算法中有关最小堆的算法，插入删除等。以及分治算法，排序算法-Algorithm for minimum heap algorithm, insert or delete. As well as divide and conquer algorithm, sorting algorithm
lvhaiya
- 实现计算器的基本功能，加、减、乘、除-Realize the basic functions of the calculator，Add, subtract, multiply, divide, etc.
View_LayoutPositionTest
- For the view test is too big, we divide the test cases into several parts.
calculator_desktop
- 实现一个简单的桌面计算器，从0-9、小数点、加/减/乘/除，以及清零键。实现高精度计算-Achieve a simple desktop calculator, from 0-9, decimal point, add/subtract/multiply/divide, and clear key. Achieve high-precision calculations
choclateBar
- This a algorithm based java program, which is published in IEEE Xtream quiz competition. this algorithm is implemented for best dividing method for divide chocklet bares among given number of people. -This is a algorithm based java program, which is
src
- a java code that uses different classes to treat various situations. a way of usig a set of data using threads and counters. it s a solution to a problem called philosophers, how to divide their time betweeen eating, playing and sleeping! a kind of
Cal24
- 任意4个1-13数字，加减乘除计算24点。 实现原理： 1）排列组合4个数字 2）计算每次排列组合的可能性-Any 4 1-13 digital, add, subtract, multiply and divide calculation of 24 points. The realization principle: 1) permutation and combination of 4 numbers The 2 possibility) calc
nearestpoint
- 随机在二维平面上生成一千个点，再利用分治算法计算这一千个点中的最近点对，并返回这两个点的距离和坐标-Randomly generated on a two-dimensional plane a thousand points, and then use divide and conquer algorithm to calculate these thousand points of the nearest point on, and return from, and coordinate t