搜索资源列表
deBoor
- de Boor 求值算法求作二次和三次B-样条曲线非插值，给定顶点-algorithm evaluates demand for secondary and cubic B-spline - curve interpolation, given vertex
deBoorCH
- de Boor 求值算法求作二次和三次B-样条插值曲线，Hartley-Judd法确定节点矢量，使用基于基的运算的插值法求控制顶点-algorithm evaluates demand for secondary and cubic B-spline interpolation curve, Hartley-Judd determine node vector-based computing interpolation method for the control vertices
bspline
- 用matlab开发的B-样条工具箱，包括B-样条近似，de-boor算法等-Developed with matlab, B-spline toolbox, including B-spline approximation, de-boor algorithm
BSpline
- 三次四阶b样条插值算法（Deboor算法）的mfc程序实现-Three fourth-order b-spline interpolation algorithm (Deboor algorithm) of mfc program
de_boor
- De Boor s algorithm is a generalization of de Casteljau s algorithm. It provides a fast and numerically stable way for finding a point on a B-spline curve given a u in the domain.
coxDeBoor
- Cox de boor algorithm for NURBS tesselation
rcs
- ：为了提高计算的精度和效率，将NURBS参数曲面应用到电大尺寸目标的RCS预估中。使用CAD软件建立模型，通 过对模型IGES文件中数据结构的分析，并以IGES文件为接口，从CAD软件模型中提取出NURBS曲面信息，然后用Cox—De Boor算法把NURBS曲面转换为Bezier益面，结合物理光学法和渐进积分展开法精确、高效的求解出任意理想导体目标曲面的 RCS-: In order to improve the calculation accuracy and effici
Doo-Sabin
- Doo-Sabin细分算法，利用de-boor算法实现对立方体的n次细分-Doo-Sabin subdivision. With de-boor algorithm to subdivision cube subdivision several times
de-boor--turbo-C2.0
- de boor 算法在turbo C2.0开发环境下的程序代码-de boor algorithm development environment in the turbo C2.0 program code
B样条曲线反求_OpenGL环境--数据点加入输出点列
- 三次非均匀B样条曲线反求:给定数据点列,反求控制点,节点向量,按照给定精度,等分参数区间,离散B样条曲线,输出离散点列,模拟真实曲线.此算法包括德布尔-考格斯算法,节点向量算法,反求控制点,以及节点插入技术.对搞图形学的朋友比较有参考作用.(Three non uniform B spline curve in reverse: given data points, reverse control points, node vector, according to the given preci
spline
- 绘制B样条曲线,以及相应的De-boor算法程序(Bspline drawing and the corresponding De-boor algorithm)
利用de Boor算法绘制B样条曲线
- 运用计算机图形学的知识，采用4阶B样条基函数，节点向量取为[0,0,0,0,1/4,2/4,3/4,1,1,1,1] 先绘制控制多边形，再用分段直线段绘制B样条曲线(Using the knowledge of computer graphics, the 4 order B spline basis function is used, and the node vector is taken as [0,0,0,0,1/4,2/4,3/4,1,1,1,1]. First, draw