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对弈
- 在1~9之间的数由玩家与电脑一步选择一个,不能选择已由任务一方已选择了的数。玩家所选的任意三个数之和(只能三个数之和)为则胜利-In the 1 ~ 9 between the player and computer from step by choosing one from the task can not choose one party has chosen a few. Players selected three the number of arbitrary and (only t