The Cantor expansion of the natural number x is

x = ak * k!+a(k − 1) *(k − 1)!+.... + a2 * 2!+a1*1!

where all the ai (digits) satisfy 0 ≤ ai ≤ i

it is easy to find a algorithm,we find the largest integer k that can satisfy 给一个正整数求出它的康拓展开

离散数学the definition first,then fix ak and substract ak * k from x,so we can fix ai ,0 ≤ i ≤ k

-Given a positive integer , find the Cantor expansion of this integer