1.　　编写程序：设计一个用来表示直角坐标系上点的位置的Location类，然后在主程序中

创建两个对象a和b，要求a在第三象限，b在第二象限，计算给定两点之间的距离并按如下格式输出结果：

a(x1,y1),b(x2,y2)

Distance = d

提示：

i.　　在直角坐标系上确定一个点的位置，需要两个坐标值（x，y）。因此，Location类的数据成员有两个，既x和y，并将其设为私有的，不允许类外的对象直接访问。

ii.　　定义3个成员函数，构造函数Location(int initX, int initY)设置点的坐标；GetX（）取得点的横坐标；GetY取得点的纵坐标。

iii.　　d2=(x2-x1)2+(y2-y1)2

-1 programming: Design a class to represent Location location points on a Cartesian coordinate system, and then create two objects a and b in the main program, a requirement in the third quadrant, b in the second quadrant, calculated for a given the distance between the two points and then output the following format: a (x1, y1), b (x2, y2) Distance = d Tip:. i determine the location of a point in the Cartesian coordinate system, two coordinate values ( x, y). Therefore, the data members Location class has two, both x and y, and set it to private, foreign object classes do not allow direct access. . ii define three member functions, constructors Location (int initX, int initY) coordinates of the set point　GetX () made the point abscissa　GetY get ordinate points. iii. d2 = (x2-x1) 2+ (y2-y1) 2