资源列表
排序选择：
oracleEntryExperience
- oracle的入门心得.oracle的体系太庞大了，对于初学者来说，难免会有些无从下手的感觉，什么都想学，结果什么都学不好，所以把学习经验共享一下，希望让刚刚入门的人对oracle有一个总体的认识，少走一些弯路。 -oracle portal experience. oracle of the system is too large, and for beginners, not to gain the upper hand will inevitably be some sense of wh
CBuilderFinancialManagementSystem.
- 全面剖析财务管理的内容，由此得出财务管理系统的需求分析和数据建模，并最终演示如何利用C++ Builder完成系统的制作-Comprehensive analysis of the contents of financial management, financial management system, the resulting demand for analysis and data modeling, and ultimately demonstrate how to use C++ B
JUANJI2
- 用C++实现的卷积公式 适合刚刚研究卷积公式的人使用-Using C++ to achieve just the convolution formula for those who study the use of convolution formula
day12
- java图形界面的课堂代码，主要处理动作，适合初学者-graphical interface of the class java code, which mainly deals with action, suitable for beginners
2005092310052013083
- 门诊收费管理系统，一个很强大的收费管理系统-Out-patient charges for management systems, a very powerful management system
jchatbox
- 一个很好的国外的聊天室，可以更换皮肤，私聊等-Abroad, a good chat room, you can replace the skin, such as私聊
CBuilderHotelManagementSystem
- 全面剖析酒店管理的内容，由此得出酒店管理系统的需求分析和数据建模，并最终演示如何利用C++ Builder完成系统的制作。-Comprehensive analysis of the content of hotel management, hotel management system for the resulting demand for analysis and data modeling, and ultimately demonstrate how to use C++ Builde
strutslogin
- 基于struts的一个java登陆系统 可以正确显示用户名-Struts a java-based landing system can correctly display the user name
shortpaths
- Given a graph G = (V, E), where every edge e has a nonnegative weight w(e), and a source vertex s in V, find the shortest path from s to every other vertex-Given a graph G = (V, E), where every edge e has a nonnegative weight w(e), and a source verte
bank2.0
- 基于struts框架的银行帐户实例，主要理清数据从用户到数据库的流程，适合初学者-Struts framework based on the bank account example, the main sort out the data to the database from the user process, suitable for beginners
20030601
- sound recorder in vb
danpianji
- 单片机实用子程序库,含有各种实用的子程序-danpianji