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stl.LCS
- 参考算法导论写的LCS算法，仿照STL的泛型风格，适用于多种STL容器中的各种类型数据构成的序列的最大公共子序列（Longest Common Subsequence）问题求解。-reference Introduction to write the algorithm LCS algorithm, modeled on the STL Generic style. STL is applicable to many types of containers data constitute the
lcs
- LCS Longest (maximum) common subsequence
lcs
- CommunicatorWebAccess全套开发部署文档.-CommunicatorWebAccess the development and deployment of a full set of documentation.
LCS
- 这是运用C++语言实现的有关最长公共子序列LCS问题的详细求解代码，大家可以下载看看，谢谢！-This is the use of C++ Language of the longest common sub-sequence of LCS to solve the problem in detail code, you can download and see, thank you!
LCS
- LCS 是一個能從輸入兩串字串當中找出最長的由左而右的順序的字元-LCS is a string which can enter the two strings to find the longest sequence of characters由左而右
LCS
- Instead of finding the longest common subsequence, let us try to determine the length of the LCS. Then tracking back to find the LCS. Consider a1a2…am and b1b2…bn. Case 1: am=bn. The LCS must contain am, we h
LCS
- LCS问题就是求两个字符串最长公共子串的问题。解法就是用一个矩阵来记录两个字符串中所有位置的两个字符之间的匹配情况，若是匹配则为1，否则为0。然后求出对角线最长的1序列，其对应的位置就是最长匹配子串的位置。 最长递增子序列LCS的实现C源码！-LCS problem for two strings is the longest common sub-string problem. Solution is to use a matrix to record the location of two
lcs
- Longest Common Subsequence Problem. Solution both Iterative and Recursive.
AlgorithmforLCS
- 自己写的，采用VB.NET编写的最长公共子序列(LCS)算法，全图形界面，VS2005下编译通过-Wrote it myself, using VB.NET to prepare the longest common sub-sequence (LCS) algorithm, the entire graphical interface, VS2005 compiler through the next
project1
- Constrained LCS. Given two sequences X, Y and a constrained sequence P, a sequence Z is a constrained longest common subsequence for X and Y with respect to P if Z is the longest subsequence of X and Y such that P is a subsequence of Z.
LCS_src
- Longest Common Substring LCS
LCS
- Longest common subsequence problem. It is dynamic approach based problem.
LCS
- lcs 最大公共字串 最大公共字串-lcs 最大公共字串 最大公共字串 最大公共字串
LCS
- 利用动态规划技术和递推的办法，求出两个字母表A和B的最大公共字串长度。-The use of dynamic programming techniques and recursive approach to find the two alphabets A and B, the largest public string length.
LCS.tar
- LCS匹配算法,divide and conquer LCS-LCS matching algorithms, divide and conquer LCS
LCS
- 最长公共字串，寻找两个字符串的最长公共字串。-LCS
LCS
- 最长公共子序列问题描述与实验目的： 序列Z=<B，C，D，B>是序列X=<A，B，C，B，D，A，B>的子序列，相应的递增下标序列为<2，3，5，7>。 一般地，给定一个序列X=<x1,x2,…,xm>，则另一个序列Z=<z1,z2,…,zk>是X的子序列，是指存在一个严格递增的下标序列〈i1,i2,…,ik〉使得对于所有j=1,2,…,k使Z中第j个元素zj与X中第ij个元素相同。 给定2个序列X和Y，当另一序列Z既是X
lcs
- lcs用来求两个字符串的最长公共子串。 -lcs of two strings to find the longest common string.
LCS-program
- 求最长公共子序列Seeking the longest common subsequence-Seeking the longest common subsequence LCS program
lcs
- 利用lcs进行的两个字符串的最长公共子序列查找。-Longest common subsequence Find the use of two strings lcs.