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c_cos
- dir1 is a subdirectory of dir2 within the same filesystem if (a) dir1 is identical to dir2 (b) dir1 s parent is dir2.
RSA
- 利用C\C++实现RSA算法的加、解密运算。 具体包括: 1)利用扩展的Euclid计算 a mod n 的乘法逆元; 2)Miller-Rabin素性测试算法对一个给定的大数进行测试; 3)实现的运算,并计算; 4)利用Euler定理手工计算,并与3)计算的结果对比; 5)实现RSA算法。并对 I LOVE NANJING UNIVERSITY OF AERONAUTICS AND ASTRONAUTICS 加解密。说明:为了方便实现,分组可以小一点,比如两个字母一组。
Zigbee
- 对Zigbee模块配置PAND ID/频点,以及数据收发流程的处理,是实际使用的代码,稳定可靠。-It s for Zigbee module Pand_ID/B value setting schedule, and send/receive code by actual product, it s stable.
prob3
- Miller-Rabin test is a primality test algorithm which determines whether a given number is prime or not. Implement Miller-Rabin primality test as given in the text book page 257, Algorithm 7.44. (aN− 1 6= 1 mod N) Write three functions to
q1
- Consider an organization with three roles: A, B and C. Whenever B has to issue some instruction to A, B has to take permission via C and then only it will be obeyed by A. This permission is issued with the help of a digital signature. A verifies
Cipher
- 置换密码算法的原理是不改变明文字符,只将字符在明文中的排列顺序改变,从而实现明文信息的加密。置换密码也叫换位密码。 试编程实现矩阵换位密码。它的加密方法是将明文中的字母按照给定的顺序安排在一个矩阵中,然后用根据密钥提供的顺序重新组合矩阵中的字母,形成密文。例如,明文为attack begins at five,密钥为cipher,将明文按照每行6个字母的形式排在矩阵中,如下形式: a t t a c k b e g i n s a t f i v e 根据密钥ciphe
hybrid-v35_64-nodebug-pcoem-6_30_223_271.tar
- 博通网卡LINUX驱动 hybrid-v35_64-nodebug-pcoem-6_30_223_271.tar,适用BCM4311-, BCM4312-, BCM4313-, BCM4321-, BCM4322-, BCM43224-,BCM43225-, BCM43227- BCM43228(These packages contain Broadcom's IEEE 802.11a/b/g/n hybrid Linux.. device driver for use with Broad
openssh-6.0p1.tar
- 搭建s s h,所,用工,具,便于x s h e l l远,程 控制l i n u x系,统,可以 完 成远 程操作,(.b a s h o f r e m o t e c o n t r o l L i n u x s y st em)