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CheatMaster_src
- Cheat Master 0.1 For DevHook with src, Real In-Game Search/Modify! -------------------------------------------------------------------------------- Intro ===== This is a prx mod written for DevHook 0.4+, which is used to search and m
TankerNet
- 与经典的《坦克大战》类似的游戏。这是一个4人对战的游戏,4个玩家两两一组,率先攻击到对方鹰巢的一组玩架获胜。它是一个C/S结构的网络游戏,它的网络部分是用重叠I/O的Socket实现的。。。编译要安装Direct8.0或以上。-with the classic "Tankedaizhan" similar game. This is a four-person war game, four players on February 21 group, the first to
cqymfx
- 最近对高性能的服务器比较感兴趣,读过了DELPHI的Socker源码WebService及RemObject之后,高性能的服务器感兴趣。 你可能需要的以下知识才能更好的读懂一个商业源码: 1).SOCKET的I/O模型熟悉掌握。 2).面向对象技术的熟悉掌握。 3).Socket的API掌握。 4).多线程技术等。 5).一门熟悉的开发工具掌握,和多种语言的源码阅读能力。
ceGUI
- My old gui. Wrote when I was 15. Good starting point if you want to make own gui system. Compile with cmd: gcc ceGUI.cpp -o cegui -lalleg -lalfont-My old gui. Wrote when I was 15. Good starting point if you want to make own gui system. Compile with c
Lianliankan-source-code-examples
- 连连看实例源代码已近上传,希望与大家交流学习,请有需要的朋友来看看,希望能够帮到大家,O(∩_∩)O~-Lianliankan nearly upload the source code examples, I hope to share with you learning, you need friends to see, want to help you, O (∩ _ ∩) O ~
A-wise-man-live
- 问题的提出:17世纪法国数学家加斯帕的一本《数学的游戏问题》描述了许多有趣问题,约瑟问题就是其中之一: 15名基督教徒和15名异教徒同乘一船航行,途中风浪大作,危机万分,领航者告诉大家,只要将全船的一半人投入海中,其余人就能幸免。大家都同意这个办法,并协定者30人围成一圈;由第一个人起报数,每数至第9人便把他投入海中,下一个接着从1开始报数,第9人又被投入海中,依次循环,直至剩下15人为止。问题是如何排法使投入海中的人全为异教徒? 编程的思路:此问题有人把它的答案隐示于下列詩句中:
Chatroom
- 这是一个包含用户界面的聊天软件,使用Java语言进行编辑。 采用了非常高效的编码逻辑,可以实现server端和client端。-It is the implementation of GUI for a chat room program. Behaviors (Server) When the server starts up, it should try to load from “accounts.dat” for saved accounts o Each account
PA1_TicTacToe
- This a Tic Tac Toe Game developed in C++ by me as a part of my curriculum.Tic Tac Toe is a two player mind game . I have developed this game in Dev C++ IDE using OOPS concepts in C++. This is a console based game. The game asks about the matrix row a
APC
- APC中文叫异步过程调用(APC)是NT异步处理体系结构中的一个基础部分。Alertable IO(告警IO)提供了更有效的异步通知形式,当IO请求完成后,一旦线程进入可告警状态,回调函数将会执行,也就是一个APC的过程。线程进入告警状态时,内核将会检查线程的APC队列,如果队列中有APC,将会按FIFO方式依次执行。如果队列为空,线程将会挂起等待事件对象。以后的某个时刻,一旦APC进入队列,线程将会被唤醒执行APC。-APC called asynchronous procedure call
hangman
- 通过一个猜字母的游戏,练习perl中的直接量列表、数组、s p l i t、j o i n、上下文和f o r e a c h循环等概念-it`s a word guess game,by which you canpractice the concepts array,datasheet,split,join and foreach of perl
TASM
- MEGA Pack of games (source code included) written in Turbo Assembler (TASM) under DOS/WinXP. Full hardware low-level things are used: VESA VBE graphics + Adlib Sound + Keyboard I/O ports. Recommended for low-level programs, students and entusiasts.