搜索资源列表
ga
- 用C语言实现的遗传算法的程序,实现的是y=x+10*sin(5*x)+5*cos(10*x)求最大值.实现环境为win-tc.-C language GA procedures, achieving is y = x 10 * sin (x 5 *) 5 * cos (10 * x) for the maximum. To achieve environmental w in-tc.
GA.通过遗传算法的思想来解决
- 本MATLAB例程，为通过遗传算法的思想来解决f(x)=x*sin(10pi*x)+2.0,-1<=x<=2的最大值问题。,The MATLAB routines for the adoption of the idea of genetic algorithm to solve f (x) = x* sin (10pi* x)+ 2.0,-1
GA
- 遗传算法，包含选择，交叉，变异等操作，可求出Y=sin(x)在0-2π的最大值和最小值-Genetic algorithm, including selection, crossover and mutation operation, etc., can be obtained Y = sin (x) at the 0-2π Maximum and minimum
ga
- 基因演算法兩個例子f(x)=x^x f(x)=cos(x)-sin(2*x)-Two examples of genetic algorithm f (x) = x ^ x f (x) = cos (x)-sin (2* x)
GA
- GA算法 一个通用的GA算法 求y=s*sin(1/x)的最小值-GA algorithm for a generic GA algorithm for y = s* sin (1/x) the minimum
GA
- 遗传算法求解最优解求函数的最大值 : f(x,y)=21.5+x*sin(4*PI*x)+y*sin(20*PI*y) | 定义域 D: -3 <=x <=12.1 , 4.1 <=y <=5.8 | | 注： 目前最好结果：f(11.6255448,5.7250441)=38.8502944790207 -failed to translate
GA
- 已知函数y=x*sin(10*Pi*x)+2.0。利用人工智能中的遗传算法（GA），计算y在区间（0，2）上的极大值。对于想学习GA的网友们来说，是个很好的Demo。而且对于基因类，已经按照面向对象的思想进行了封装，稍微修改参数就可以用在实际项目中。-Known function y = x* sin (10* Pi* x)+2.0. The use of artificial intelligence in the genetic algorithm (GA), calculating y i
vcDEMO
- 已知函数y=x*sin(10*Pi*x)+2.0。利用人工智能中的遗传算法（GA），计算y在区间（0，2）上的极大值。对于想学习GA的网友们来说，是个很好的Demo。而且对于基因类，已经按照面向对象的思想进行了封装，稍微修改参数就可以用在实际项目中。 实现环境：Visual C++ 6.0. -Known function y = x* sin (10* Pi* x)+2.0. The use of artificial intelligence in the genetic algorit
Max2
- 解决f(x,y)=(sin(x)/x)*(sin(y)/y)的GA算法-GA algorithm to solve f(x,y)=(sin(x)/x)*(sin(y)/y)
matlab_GA_7.0
- 基于MATLAB7.0，求函数f=x+10*sin(5*x)+7*cos(4*x)的最大值点，简单的单点交叉，基本位变异，赌轮盘选择.-Based on MATLAB7.0, find the function f = x+10* sin (5* x)+7* cos (4* x) the maximum point, a simple single-point crossover, the basic bit mutation, gambling roulette wheel.
GA
- 遗传算法应用程序使用说明： 1.安装MATLAB5.X； 2.建立目录：(c:\GeneticProgram),并将这里提供的所有源程序拷入该目录； 3.运行(c:\GeneticProgram)中的 startup； 4.在MATLAB Command Window内直接运行程序 FloatExample和BinaryExample。 FloatExample和BinaryExample分别采用浮点编码和二进制编码方法，求函数 y=20+x + 10*sin(
GA_min
- 利用GA演算法，求解二元二次函數的最小值及其對應之x,y值 原函式為：sin(sqrt(x^2+y^2))^2)/(1+0.01*(x^2-y^2))^8 x與y值的範圍皆從-2~2間-GA algorithm solving binary quadratic minimum of the function and its corresponding x and y values of the original function: sin (sqr
GA
- 遗传算法的设计与实现 y=x.*sin(10*pi*x)+2 - Genetic Algorithm Design and Implementation y=x.*sin(10*pi*x)+2
ga
- 遗传算法实现计算f(x 1,x 2 )= 21.5 +x 1 ·sin(4πx 1 ) +x 2 ·sin(20πx 2 )的最大值-calculate the maximum value of f(x 1,x 2 )= 21.5+x 1 ·sin(4πx 1 )+x 2 ·sin(20πx 2 ) by Genetic Algorithm
GA
- 以求f(x)=10*sin(5x)+7*cos(4x) x∈[0,10]最大值为例，详细讲解并实现了遗传算法各个阶段的编程 -Take to solve the maximum of f(x)=10*sin(5x)+7*cos(4x) x∈[0,10] for example, to explain in detail the various stages of the programming and implementation of Genetic Algorithms
ga
- 遗传算法代码求解0到10之间10*sin(5x)+7*cos(4x)的最大值-Genetic Algorithms for Solving Code 10* maximum sin (5x)+7* cos (4x) between 0-10
ga
- 基因演算法兩個例子f(x)=x^xf(x)=cos(x)-sin(2*x)-Two examples of genetic algorithm f (x) = x ^ x f (x) = cos (x)-sin (2* x)
ga
- 基因演算法兩個例子f(x)=x^xf(x)=cos(x)-sin(2*x)-Two examples of genetic algorithm f (x) = x ^ x f (x) = cos (x)-sin (2* x)
ga
- MATLAB遗传算法源程序：用遗传算法求解y 200*exp(-0.05*x).*sin(x)在[-2 2]区间上的最大值-MATLAB genetic algorithm source code: using genetic algorithm to solve y 200* exp (-0.05* x).* Sin (x) in the [-2 2] interval on the maximum
GA
- 使用java实现遗传算法，求出max{f(x1,x2)=21.5+x1*sin(4*π*x1)+x2*sin(20*π*x2)}的最优解 约束条件为 -3.0<=x1<=12.1 4.1<=x2<=5.8(The use of Java genetic algorithm, calculate the max{f (x1, x2) =21.5+x1*sin (4* PI *x1 +x2*sin (*x2) 20* PI)} of the optimal solutio