搜索资源列表
jing
- 简单的小游戏，井字棋，c++源码。基于console编写-Simple game, tic-tac-toe game, c++ source code. Prepared based on the console
jinziqi
- 井字棋游戏基于剪枝算法，是博弈树搜索算法的一个重要分支-Pruning algorithm based chess game Tic Tac Toe is game-tree search algorithm is an important branch
jzq
- 这是一个可以进行人与人对战的井字棋小游戏，非常简单，适合初学者-All Battle chess game of Tic-Tac
well-chess
- 原创井字棋游戏源代码，希望对大家有所帮助-The well character chess game the source code
jingziqi
- #include < iostream> 井字棋using namespace std const int n=3 int block[n][n]={0,0,0,0,0,0,0,0,0} void draw(int **,int x,int c) -# Include < iostream> using namespace std const int n = 3 int block [n] [n] = {0,0,0,0,0,0,0,0,0} void draw (int*
Tic_Tac_Toe
- html5井字棋小游戏，实现人机对弈，红色叉代表玩家，绿色圈圈代表电脑。-html5 Tic-tac-toe game, man-machine chess, a red cross on behalf of the players, the green circle on behalf of the computer.
vb
- vb程序语言编译的井字棋游戏，这是详细的源代码。-Well character chess game with source code
Morpion
- 该程序使用了socket实现一个简单的井字棋游戏。-realisation of a simple game Morpion with socket
TTT3D
- 井字棋游戏，可以和计算机对下，ai有一定的智商，不容易输给玩家-Tic-tac-toe game, and the computer can be under, ai have a certain IQ, is not easy to lose players
TicTacToeWithGUI
- python写的带GUI的井字棋游戏，仅供参考-python game
main
- 读入一个整数，表示井字棋棋盘的边长。判断其中是否存在某一方获胜，获胜的条件是存在整行或整列或整条对角线或整条反对角线上是相同的棋子。如果存在，则输出代表获胜一方字母：X或O（大写字母X或O）；如果没有任何一方获胜，则输出NIL。-Read an integer, said tic-tac-toe chess board side length. Determine whether there is a party wins, the winning condition is the entire
TicTacToe
- 一个井字棋小游戏 横向 竖向 斜向三个则赢-tic toe tac game
Tic-Tac-Toe
- 井字棋c#windowsform源码 代码简单 功能完善,不支持人机对战-Tic-tac-toe c# windowsform source code for a simple function perfect, does not support the man-machine war
JZQ
- 利用极大极小值搜索算法实现井字棋游戏，包含一些优化算法过程-Use Minimax search algorithm Tic-tac-toe game, including some optimization process
mfcjing
- 井字棋网落版，实现了简单的通信功能，第一个启动默认为服务端，第二个启动默认连接到服务端。-Tic-tac-toe online version, to achieve a simple communication functions, first start the default for the service end, a second end connected to the service start by default.
jingziqi
- #include < iostream> 井字棋using namespace std const int n=3 int block[n][n]={0,0,0,0,0,0,0,0,0} void draw(int **,int x,int c) -# Include < iostream> using namespace std const int n = 3 int block [n] [n] = {0,0,0,0,0,0,0,0,0} void draw (int*
C_Cross
- 井字棋,c实现，基本的text图形表现。-cross chess
Jingziqi_Java
- 通过检查每一行，每一列，每个对角线和反对角线实现井字棋游戏-By examining each row, each column and each diagonal and anti-diagonal realization Tic-tac-toe game
GameSearch
- 井字棋的有关java的alphabeta搜索-Tic-tac-toe game java on the alphabeta search
GameSearch
- 井字棋的有关java的alphabeta搜索-Tic-tac-toe game java on the alphabeta search