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fabianyi
- 未优化模式就是原生代码,其调式期间可以和源代码一 一对应,maxspeed模式则尽可能将操作放在寄存器内完成,并且有一定的算法优化;而最小代码模式则通过合并部分代码,尽可能的通过EBP比例变址寻址,完成对二维数组的访问。 -Model is not optimized native code, and its modal period of the source code can be one correspondence, maxspeed model is designed to opera
sanweidixing
- 将固定大小的地形高值二维数组转化为三维地形表示-The topography of high-value fixed-size two-dimensional array into a three-dimensional terrain that
a
- 该程序计算元胞自动机凝聚扩散的实例,附加判断二维数组的元素及其个数-The program calculated the proliferation of cellular automata examples of cohesion, the additional two-dimensional array to determine the number of elements and their
Lab6-1
- 数据结构中二维数组的实现代码,利用三元组形式-Two-dimensional array data structure in the implementation of the code, using the form of triples
cyuyan
- 用c语言编写的小程序,包括:1.给固定的方块图形填涂颜色;2.随机给二维数组赋值。3.键盘操作。-With a small c language programs, including: 1. To a fixed box graphics Tiantu color 2. Were randomly assigned to two-dimensional array. 3. Keyboard operation.
hello
- 动态规划的是思想实现,快速查找最长公共字串的问题(二维数组和一维数组的实现)-adapt the DP to solve the common longest strings(two and one dimension array)
gradesofstudents
- 利用二维数组对学生的成绩进行统计并输出结果打屏幕上-The use of two-dimensional array of statistics on student performance and output on the screen to play
shuanfa2
- 求图的任两结点间的距离,(2) 用二维数组存放C和A ,C是原成本矩阵,A 是求出的距离矩阵 (3) 算法采用三重循环,其中最外层的循环变量必须代表中间结点,中层的循环变量代表头结点而内层循环变量代表尾结点。 (4) 试着把三层循环变量的顺序作些改变,最外层的循环变量仍代表中间结点,而中层循环变量代表尾结点,内层循环变量代表头结点。把两种做法所得结果作比较,看结果是否相同 (5) 显示结果要清晰易懂 (6) 本题运行结果 -Order to map any of the di
shuanfa3
- (1) 用一个4*20的二维数组M,第1行存放按从小到大排序的20个所给出的ai和bi,第2行存放相应的作业序号,第3行存放1或2(1代表是来自ai,2代表是来自bi), 第4行存放0或1(0代表作业序号未进入最优调度方案;1代表作业序号已进入最优调度方案) (2) 排序完后,按课本所述方法求一种最优调度方案,存放在S中。 -(1) with a 4* 20 two-dimensional array M, the first a line to deposit a small to l
javacode
- 布局与组键大小问题、定义接口与接口的继承、面板的基本使用、事件驱动器的编程、二维数组的输入与显示-Group key layout and the size of the problem, define interfaces and interface inheritance, the basic use of panels, event-driven programming device, two-dimensional array of input and display
migong
- 从入口处摸墙求解,利用循环通过对墙壁的触摸来寻找出口。规定迷宫为一个二维数组,迷宫入口在二维数组第一行,出口在二维数组最后一列。-From the entrance to touch the wall solving, use of loop through the walls of touch to find export. The provisions of the maze for a two-dimensional array, the maze entrance in the two-
HotelMangement
- 一个简单的酒店管理平台,酒店管理系统控制台版本 10层 12房间/层--》二维数组 输入search可以查询全部房间的状态 输入in 输入姓名房间号zhangsan 102显示张三入住102 输入out 102显示退房 输入quit退出系统-A simple hotel management platform, hotel management system console version of the 10-story 12 room/floor- " two-di
array
- 动态申请/释放二维数组,所用语言有C和C-Dynamic applications for two-dimensional array
erweishuzu
- 求二维数组每列中的最小元素,并依次放入PP所指的数组中-Seeking two-dimensional array of elements
binary
- 用labview实现图像的二值化,通过把图片转化为二维数组,通过和阈值比较把图像二值化-Achieved with labview binary image by the image into a two-dimensional array, and the threshold value by comparison to image binarization
2
- 1.请编写一个函数void fun(char *tt,int pp[]),统计在tt字符中"a"到"z"26各字母各自出现的次数,并依次放在pp所指的数组中。 2.下列程序定义了n×n的二维数组,并在主函数中赋值。请编写函数fun,函数的功能使求出数组周边元素的平均值并作为函数值返回给主函数中的s。-1. Please write a function void fun (char* tt, int pp []), statistics tt characters " a&qu
7-8
- 找出一个二维数组中的鞍点,即该位置上的元素是该行上最大,在该列上最小。也可能没有鞍点。-Find a saddle point in two-dimensional array, that is, the position of the element is the bank' s largest and the smallest in the column. May not have saddle points.
fapai
- 遍历二维数组,查找值为card的元素,输出对应的花色和面值-Two-dimensional array traversal to find the element value card, the output corresponding to the color and the face value
DWR
- DWR实例,字符串、带参的字符串、数组、集合、Map、循环Map、二维数组-DWR example, the string with parameter string, array, collection, Map, cycle Map, two-dimensional array
08150851
- 从一个迷宫的入口到出口找出一条可通路经。用一个二维数组MG(1:M,1:N)模拟迷宫,数组元素为0表示该位置可以通过, 数组元素为1表示该位置不可以通行。MG(1,1)和MG(M,N)分别为迷宫的入口和出口。 -From the entrance to the exit of a maze to find an available path through. With a two-dimensional array MG (1: M, 1: N) simulated maze, an ar