资源列表
PIC16F877A--
- 很实用的多任务结构,UCOS的精髓，任何MCU都可以用对ROM没要求,单线通信为例，带PIC16F877A的PROTEUS仿真-Practical task structure, the essence of UCOS, any MCU can not require in ROM, single wire communication, for example, taking PIC16F877A PROTEUS simulation
blcak
- 实现黑白棋游戏的简单功能，易上手，编程方式比较方便。-To achieve a simple function of the black and white chess game, easy to use, easy to use programming.
Samples
- 详细说明：中控指纹采集仪VB开发DEMO，只要你到中控官网下载指纹采集仪驱动安装后参考本案例即可成功开发指纹采集软件了哦。--In the control fingerprint VB development DEMO, as long as you to control the official website to download the fingerprint collecting instrument drivers installed refer to the case to the
LoanCal
- 用C#语言写的贷款计算器，这个计算器能够根据用户给出的贷款金额、贷款期数、贷款日期、还款方式、贷款种类，计算出相应的还款计划表。-C# language to write the loan calculator, the calculator can be given by the user according to the loan amount, the loan installments, the date of the loan, repayment methods, types of
duoxiancheng
- 易语言简单多线程演示，特别适合于新手学习-Yi language is simple multi-threaded demonstration, particularly suitable for novices to learn! !
houtairenwu
- 后台任务线程演示源码，带进度条演示源码，适合学习使用！-Background task thread demo source code, with a progress bar demo source code, suitable for learning!
daeega
- 易语言*处理源码，可助易语言开发的软件过 360杀毒误报，已测试成功-Easy language processing source code free to kill, can help easy language software developed over 360 anti-virus false positives, has been tested successfully! !
dwaddcc
- RING3部分直接用了C++代码 LO.e 是驱动代码 实现了驱动的基本功能 创建链接符号等等 先运行Dbgview.exe 选中capture capture kernel 再运行LOApp.exe 输1,2...回车看看输出 -RING3 section of code directly with the C++ too lazy to use easy language to write code LO.e is driving the basic func
JCage-Cracked
- Java Remote control-Java Remote control.........
JSpy
- Java Remote Control-Java Remote Control..............
jRAT-v2_1.2
- Java Remote Control-Java Remote Control..............
Banker
- 对I/O系统的死锁资源的问题的解决主要的方法是银行家算法，单种资源的银行家算法和多种资源的银行家算法的解决思路一致，要求设计实现多种银行家算法，并要求所涉及的模型最少更够满足如下要求： (1)程序能够根据进程的请求进行判断，给出系统是否安全的的提示，如果安全，要求能够显示一组进程执行的安全序列； (2)能够根据需要，显示当前系统中各种资源的分配情况；-The problem I/O system deadlock resources to solve the main method is