资源列表
TM1629BSHIZHONG
- 本时钟是有TM1629B+STC89C52+8563A是用一个电饭锅面板做的-The clock is TM1629B+ STC89C52+ 8563A is a rice cooker panel do
PIC18F4520eight-AD-resource-code-
- This ZIP file include 8 AD resource code for the PIC18F4520.these samples are good for test and program-This ZIP file include 8 AD resource code for the PIC18F4520.these samples are good for test and program
lfmcw_sil
- 雷达应用领域，对于线性调频连续波测目标中所产生的三角波泄漏，采用对消法进行去除，偏学术，已成功应用于专利中。-Radar applications, for the triangular wave leakage linear frequency modulated continuous wave measured target generated by the cancellation method using removal, partial academic, it has been su
myEmile
- VFP中调用jmail.dll实现的邮件收发小程序，包括VFP程序源码。-VFP Emile
homework-1
- 建立数学模型求解造船问题，使总支出费用最小。采用lingo软件针对数学规划问题建立模型，编写程序求解。-Problem solving mathematical model shipbuilding, bringing the total expenses to a minimum. Lingo software using mathematical programming model for the problem, write a program to solve.
homework-2-1
- 针对这个问题：假定所有住宅需要提供相同数量的服务，选择一个服务中心，使得到它们所有住宅总任务量最小。（任务量等于服务数和距离的乘积），采用lingo软件建立模型编程求解-To address this issue: Assume all residential need to provide the same amount of service, a service center, so that they all get the minimum amount of total residen
techinique
- ACM经典算法和数据结构，对初学者有很大帮助，欢迎下载学习。-Data strcture.
homework-2-2
- 对以下问题：假定不同的住宅有不同的服务量，值为c [2 1 2 4 4 2 5 1 6 1 1 1 4 2 6 2 1 2 4 5]。重新计算服务中心的地址和服务方案。采用lingo软件建模，编程求解-On the following question: assume different homes have different amounts of service, value c [2 1 2 4 4 2 5 1 6 1 1 1 4 2 6 2 1 2 4 5]. Recalculati
homework-2-3
- 在（2）的基础上，另外假定服务中心可以设定3个，一个主中心和两个分中心，要求分配的服务量之比为2：1：1，而且规定一个住宅只能由其中一家服务中心提供服务。如何选址并且给出每条路线上的运输量。 -In (2), based on a presumption service center can be set to three, one center and two sub-centers, the amount of the request for allocation of service
high-compute
- ACM 高精度计算问题介绍和相关代码，对初学者有较大帮助。-the technique of high jingdu compute.
jisuanjihe
- ACM计算几何问题介绍和相关代码，对初学者有较大帮助。-ji suan ji he wen ti.
Courseware-Numerical-Analysis-Course
- 西电数值分析课程所有的课件，非常全面，很有参考价值-Xi an University of Electronic Science and Technology Numerical Analysis Course all courseware, very comprehensive, a good reference value