资源列表
一个最简单的聊天程序
- 适合初学者 先运行服务器端再运行客户端-for beginners first running server-client running again
给托盘添加右击菜单--变化的背景图
- 一般的商业程序都有托盘图标和在托盘上弹出右击菜单的功能，那么如何给自已的程序添加这样的功能呢？本文通过改变背景图的实例，介绍一种实现托盘上弹出右击菜单的方法-general commercial processes tray icon in the tray and right click on the pop-up menu function, then how to add their own procedures for such functions? By changing the co
VC写的windows虚拟桌面
- 类似Linux下的虚拟桌面。可以给大家一个不一样的感觉。-similar to the virtual Linux desktop. Can give us a different feeling.
水晶报表控件的示例程序源码
- 水晶报表控件的示例程序源码，包括VB，VC的代码。CrystalReports8.5,CrystalReports.net 的代码。-Source Code of CrystalReport Examples, including source code of VB and VC. The code of CrystalReports8.5,CrystalReports.net.
cpucounter
- Intel提供的获取某台机器CPU数量的源代码-It showed how to get the CPU count of your computer. it come from Intel.
2catwork0506
- 计算MDI子窗口数,仅显示文件夹的打开对话框-calculate the numbers of MDI subwindows, only display the dialog box of the folders.
autoricheditctrl_src
- 多功能编辑控件源代码:autoricheditctrl_src-multifunction controls source code editors : autoricheditctrl_src
CODE_UPLOAD1262112122000
- 老外写的串口程序，看起来还不错，大家看看吧-foreigner to write Serial procedures, was looking good and we look at it
Bresenham_Middle_line
- 图形直线中点生成算法,Bresenham画直线,Bresenham画椭圆-This is a arithmetic of Bresenham_Middle_line.It draw line and ellipse acrossed Bresenham.
middle_bresenham_Line0
- 图形画椭圆与圆弧中点算法类似：确定一个象素后，接着在两个候选象素的中点计算一个判别式的值，由判别式的符号确定更近的点-To draw a ellipse,similar to the middle point of arc:after determine a pixel,calculate the value of a judge expression,according to its sign,determine the nearer point.
middle_bresenham_Arc
- 基本原理 假定初始点P0 ∈G0，沿某方 向(假定为X轴）前进△X时，到 达G+或G-(假定为G-)中的P1,在 沿另外一方向(Y轴)前进△Y,到 达P2。若P2 ∈G+，则改变前进 方向，否则继续向G+前进。-Basic Principle: First ,initial point Pzero,assumed that Pzero belong to Gzero,moves the distance deltaX along one direction,assuming X axes,a
middle_bresenham_Circle
- 基本原理 假定初始点P0 ∈G0，沿某方 向(假定为X轴）前进△X时，到 达G+或G-(假定为G-)中的P1,在 沿另外一方向(Y轴)前进△Y,到 达P2。若P2 ∈G+，则改变前进 方向，否则继续向G+前进。-functional:assume orient point P0 in G0,go along cX on some direction(assume x axial),arrive P1 in G+ or G-(assume G-),go along cY on another di