资源列表
Line-Clip
- draw line midpoint algorthim
fileOperate
- windows文件操作，文件移动、删除操作-windows file operations, file move, delete operation
musicFlex-flex
- 基于flex编写的一个music项目，初学者可借鉴参考一下，进行flex熟悉-Based on flex written in a music program, beginners can learn reference, flex familiar with
main
- 利用堆栈原理，对括号是否成对进行判断。-The use of the stack to judge whether pairs of brackets
WallPaperChanger
- Change the wall paper in Windows programmaticaly
Ex1
- 从屏幕输入字符 判断括号匹配问题 数据结构作业-Judgment parenthesis matching data structure operations input characters from the screen
scaner
- 编译原理扫描器，按照有限自动机和词法分析器的原理制作而成。-The compiler theory scanner, made in accordance with the principle of finite automata and lexical analyzer.
xueshengchengjiguanli
- 简单的C++学生成绩管理系统 适合新生 课程设计-Simple C++ student achievement management system suitable for the freshman curriculum design
RAW8ToRGB24
- 本程序可以实现8位灰度图像转换为24位bmp位图。-The program can achieve 8-bit grayscale image is converted to a 24 bitmap bmp.
JoseQuestion
- 约瑟夫环问题求解 约瑟夫环问题的具体描述是：设有编号为1，2，……，n的n(n>0)个人围成一个圈，从第1个人开始报数，报到m时停止报数，报m的人出圈，再从他的下一个人起重新报数，报到m时停止报数，报m的出圈，……，如此下去，直到所有人全部出圈为止。当任意给定n和m后，设计算法求n个人出圈的次序。-Josephus Josephus problem solving specific descr iption is: has numbered 1, 2, ...... n n (n
Gaussuanfilter
- 本程序实现：读取三维图像裸数据，三维图像的高斯滤波，三维数据的保存。-The program: read a three-dimensional image bare data, three-dimensional image of the Gaussian filter, the preservation of the three-dimensional data.