资源列表
ch7_14_1
- 输入学生课程成绩，求每个学生平均分，求每门课程平均分，输出每个学生每门课程成绩，输出每个学生的平均分，输出每门课程平均分。-Input of the student score, average score for each student, for each course average, each course achievements of the output of each student, output of each student s average output score f
zhengguishi
- 编译原理实验 将任意的正规文法转换为相应的正规式。 -Convert any normal grammar to the corresponding normal form
Socket
- 网络传输，TCP/ip客户端和服务器端。数据传输稳定可靠。-Network transmission, TCP/IP client and server. Stable and reliable data transmission.
cut-serious
- 基于windows下对可时序序列进行切片的程序，切片大小为5个序列-Based on the windows can be programmed timing sequence slice, slice the size of five series
tansform-linux-systerm-call-to-num
- 实现在windows下将Linux系统调用转换成系统调用号-Realized in the windows system calls into the Linux system calls
transform-linux-systerm-num-to-call
- windows 下c#程序实现对Linux系统调用号转换成系统调用序列-windows under c# program to realize the Linux system call numbers into the system call sequence
dfs0-1
- dfs回溯方法解决0-1背包问题。 对比dp减小了空间复杂度-dfs 0- 1
jixu
- 词法分析器，每个循环处理一个单词；调用词法分析过程；输出每个单词的内部码（种别编码，属性值）。建议从文件中读取要分析的符号串。-Lexical analyzer, each cycle dealing with a word lexical analysis procedure calls the output of each internal code word (species not coding, property values). I recommend reading the s
FindStudent
- 把长度为l1,l2…ln 的n个程序放在磁带T1和T2上，并且希望按照使用最大检索时间取得最小值的方式存储，即如果存放在T1和T2上的程序集合分别为A和B，则希望所选择的A和B使得max{∑li 1,∑li2}(i1属于A，i2属于B)取得最小。 使用回溯法实现-The length of L1, L2... Ln n programs put in the tape on T1 and T2, and hope that in accordance with the maximum searc
restricted-boltzmann-machines-master
- 深度学习 rbm 学习受限波特字母机的好材料-Porter limited depth study rbm machine learning good materialr
neuro
- Easy sample for NeuralNetwork
Matrix
- C++实现的矩阵操作，包括计算行列式、求最大最小值及其下标、矩阵求逆、转置等功能-Matrix operations C++ implementation, including the calculation of the determinant, find the minimum and maximum values and subscr ipt, matrix inversion, transpose function