资源列表
LicenceManager
- This a simple Licence management system. And this is a homework for OO class. Not very strong.-This is a simple Licence management system. And this is a homework for OO class. Not very strong.
jisuan
- 简单计算器的C_++实现代码，属于控制台，比较适合初学者-The simple calculator C_++ achieve code belonging to the console, and more suitable for beginners
aa
- 数据结构和常用算法C++实现，是一个很好的参考。希望对大家有帮助。-The data structure realization of commonly used algorithm C++ of a good reference. I hope everyone has to help.
Ping
- PING命令的实现，包含了底层网络通信，以及如何反馈信息。-The realization of the PING command contains the underlying network communication, and how feedback information.
AutoSetupSQLServer
- 能够自动启动控制台安装SQLServer，要求跟SQLServer安装介质放在同一个目录底下。全自动安装，不需要交互干预。-Can automatically start the console to install the SQLServer, require to be placed under the same directory with the SQL Server installation media. Automatic installation, do not need to e
circle
- 这是我为我孩子写的程序，输入园 的半径，求出周长和面积-this program is for my children,insert radius the program will find the c and s of circle
BANK
- 银行卡管理系统开户、存款、取款、修改密码、重置密码、销户 c-#include<iostream> #include<cstring> using namespace std class count { public: friend class ATM count (char Name[],char Num[],float Money,char Password[]) //初始化
arp
- 利用VC++6.0开发网络编程，本人已运行，好用-VC++6.0 development network programming, I have to run, easy to use
2
- 有1、2、3、4个数字，能组成多少个互不相同且无重复数字的三位数？都是多少？ -1, 2, 3, 4 numbers, how many can be composed of different from each other and no redundant digital three figures? All is a number?
Desktop
- 输入两个正整数m和n，求其最大公约数和最小公倍数。利用辗除法。程序源代码：-Import two positive integer m and N, seek the greatest common divisor and the least common multiple. The use of rolling division. Program source code:
Desktop
- 字符串strcpy的编写，对字符串strcpy重新编写。可知道系统内部的具体实现-String to string strcpy strcpy write, rewrite. Know the system concrete realization
Desktop
- 字符串strcmp的编写，对字符串strcpy重新编写。可知道系统内部的具体实现-String to string strcpy strcpy write, rewrite. Know the system concrete realization