资源列表
乳猪
- 一个多线程同步问题. 哲学家进餐问题!! java实现-a multithreaded synchronization. Dining Philosophers problem! ! Java Implementation
reg
- Register/Unregister com server
CH19
- c的几个代码，本人珍藏版！！！！！！！！谢谢，请让我加入把-c Several code, I Collector Edition! ! ! ! ! ! ! ! Thank you, please allow me to join the
wrls-AODV.tcl.tar
- A 3-node example for ad-hoc simulation with DSDV
String
- 字符串的匹配算法，简单的c++算法源码，一共三个文件，文件s和t中存放字符串-String matching algorithm, a simple c++ algorithm source, a total of three documents, document storage s and t in the string
buffer
- this program solves an Income Fluctuation Problem requires obj.m function which is the RHS of the Bellman equation as a function of c=consumption and x=cash in hand-this program solves an Income Fluctuation Problem requires obj.m function w
3_3
- 主要实现计算中 各种 制式之间的相互转换-the funtion of accout
doanproject
- the method of feature extraction using pca and k nearest neighbor for recognition
ci
- 磁力正演程序，王老师的杰作。可以用来计算全空间任意点的磁场。-Magnetic forward procedure, Wang s masterpiece. The whole space can be used to calculate the magnetic field at any point.
dcb
- 串口通讯函数类型 dcb的结构-Communication function type dcb structure
p_c
- 生产者消费者问题，生产者向缓冲区写，通过进程间的同步，消费者读出缓冲区中的内容。-Producers and consumers, producers write to the buffer, through inter-process synchronization, consumers read out the contents of the buffer.
com
- 该文件能够实现对COM口的初始化，以及读取COM口的信息 。-uart_init read