资源列表
15577661
- 递归求字符串长度 许多公司的面试题目，找工作的人可以-recursive string length for the many interview subjects, people looking for work can s
112255
- 输入一个数字，以螺旋的方式向里面递加，最终形成一个方阵。要面试的同学建议-importation of a number of ways to screw to the inside of progressive, ultimately form a matrix. To interview the students look at the recommendations
11register
- 寄存器的实用范例，相信看了本源代码会对寄存器有个清晰的了解-Register of practical examples that read code will register origin have a clearer understanding of
11LinkList
- 链表的源代码，分为带头节点的链表，不带头节点的链表。-Chain source code into the lead in the linked list node, the node does not take the lead List.
11332
- 一个数学求值的源代码，一个公司笔试题目的编程实现，c语言初学者可以参看-a mathematical evaluation of the source code, a company of the written language, c language learners can see
Winamp样式的自动停靠对话框
- Winamp样式的自动停靠对话框-Winamp-style automatic berth dialog
QuickWin_src
- 如何在界面中调用一个程序并返回运行结果-how to transfer a program and return the result in interface
programs
- 一个可以将大文件分割的小程序。注意写路径得时候最后一个文件夹一定要加上\\，文件编号从0开始-a large file can be divided in small programs. Path to write the final time in a folder must add \\, document number, starting from 0
DropExDemo
- 扩展COleDropTarget类来支持任意窗口拖放-sustain windows drag though COleDropTarget cla
GWTTest
- 如何获得另一个应用程序窗口中的文本-how to access another application window text
TestMouse
- 测试鼠标位置的源程序-test mouse location of the source
fraction
- 这是个基础的程序，请大家指点指点！我的Q：137851600，邮箱lbz_898236@126.com-This is the basis for the procedure, please pointing out the instructions! My Q : 137851600, mail lbz_898236@126.com