资源列表
primary
- 有n个整数，使其前面各数顺序向后移m个位置，最后m个数变成最前面的m个数 -There are n integers to move back in front of the order of the number of m-position, the last m into the top of the number of the number of m
nmax
- 题目：有n个人围成一圈，顺序排号。从第一个人开始报数（从1到3报数），凡报到3的人退出圈子，问最后留下的是原来第几号的那位。-Title: There are n individuals form a circle, the order Paihao. The number of individuals starting from the first report (from 1 to 3 reported numbers), who report to three people out of
for
- labview 6.1，FOR 循环函数，计算1+2+3...相加的和。-labview 6.1, FOR loop function, calculate the sum of 1+2+3 ... and.
N
- 利用labview里的FOR循环函数计算N次阶数的和。-Use labview inside the FOR loop function of the number of second-order calculation of N and.
max@min
- 利用labview程序计算一个数组的最大值和最小值分别是多少-Calculate a set of arrays are the maximum and minimum number of
rabbit
- 兔生子程序源代码，详细算法，程序简单易懂-rabbit
4
- labview程序，利用4个数据求平均得到滤波后的函数波形。-labview program, using an average of four data seeking function of the waveform to be filtered.
Curso_de_PICs_-_Arquitectura_de_los_PICs
- Important piece for developing cmps03 code
lcd_1602
- LCD1602显示 在LCD显示屏上显示特定的一个字符串-lcd1602 display
CUMCM
- 对1993—2008年内全国大学生数学建模竞赛所有试题（A组）进行整理并整理了相应知识点-During the year of the 1993-2008 National Undergraduate Mathematical Contest in Modeling for all examination questions (A group) to collate and organize the corresponding knowledge point
lxswt
- 旅行商问题 用lingo语言解出一个完整的最短回路
Lingolindo
- 该程序是lingo以及lindo的一些教程，同时也包括了一些源码。-The program is a lingo, as well as lindo some of the tutorials, but also includes some source code.