资源列表
MediaPlayer
- 自己做的BREW 音乐播放器 用C语言写的-BREW to do their own music player
yb
- 我做的一个自己的网页，费了不少心思 希望大家多多批评-I did a own web page, ve done a lot looking forward for your criticism
carlicense
- 车牌识别系统，一个比较实用的程序，不过移植性不是很高-License plate recognition system, a more practical procedure, but portability is not very high
P2P
- p2p的服务端和客户端 用c实现的 用于实时通话-p2p service and client to use c implementation for real-time call
queen
- 皇后问题，用于c++课程设计，每一个皇后可以吃掉棋盘上横、竖和对角线上的所有棋子，要求在棋盘上放入至少3个棋子-Queens problem, for c++ program design, the Queen can eat each board horizontal, vertical and diagonal all the pieces, called the board into at least three pieces
createtu
- 用邻接矩阵创建图并将其输出：本程序可以有四种图形式：分别为有向图，无向图，有向网，无向网；-Create a map with the adjacency matrix and the output: This program can graph four forms: namely a directed graph, undirected graph, the network, not to the network
Input+USBIC
- USBIC+89S51(using Baudrates 9600)
maxloading
- 有两艘船，n 个货箱。第一艘船的载重量是c1，第二艘船的载重量是c2，wi 是货箱i 的重量,且 w 1+w2+……+wn≤c1+c2。 我们希望确定是否有一种可将所有n 个货箱全部装船的方法。若有的话，找出该方法 采用分支法求解-Two vessels, n a cargo box. The first ship load is c1, the second ship of the load is c2, wi is the weight of containers i
maze
- 迷宫是许多小方格构成的矩形，在每个小方格中有的是墙（图中的“1”）有的是路（图中的“0”）。走迷宫就是从一个小方格沿上、下、左、右四个方向到邻近的方格，当然不能穿墙。设迷宫的入口是在左上角(1,1)，出口是右下角(8,8)。根据给定的迷宫，找出一条从入口到出口的路径。 采用分支法求一个解-Maze is composed of many small rectangular box in each small box in plenty of wall (in the figure &
nqueens-recursion-backtracking-n^n
- n皇后问题的递归回溯实现， 状态数：n^n-n queens problem of recursive backtracking implementation, the number of states: n ^ n
adjgamma
- iris recognition iris gamma adjust
TriangleNextdayCommission
- 这里面有3个c语言程序，一个是判断三角形，一个是计算下一天，一个是计算佣金-This inside 3 c language program, one is to judge the triangle, one is calculating the next day, a commission is calculated