资源列表
83274902RSA
- 这是一个RSA的简单实现算法,用的是C++语言实现的. RSA加密算法的vc实现，可以实现1024位的加密 -This is a simple realization of RSA algorithm is used in C++ language to achieve. RSA encryption algorithm to achieve the vc, the 1024 can be encrypted
RSAvc1985
- 用vc++6实现的一个RSA加密程序，功能比较齐全，运行界面比较漂亮, 简单的RSA算法的加密解密程序，带MFC界面的 -Vc++6 to achieve using a RSA encryption process, complete functions, run the more beautiful interface, simple RSA encryption and decryption algorithm procedures, interface with MFC
734939RSA
- rsa算法源程序，C代码.信息安全rsa非对称加密算法用c语言编程实现 rsa的C语言实现 gcc 3.4.2编译通过 -rsa algorithm source code, C code. information security rsa asymmetric encryption algorithm using c language rsa the C programming language compiler gcc 3.4.2 through
pingcode
- 这是在Unix环境下编译和链接成功的实现网络通信的ping命令的完整源代码。-ping source code distribute by cpu || digger. For unix family only. compil and link success in sco unix.
Qt_Develop
- 优龙科技提供的一个在QTE2.3.7环境下编译简单程序的技术文档，比较有参考价值！-Excellent technology to provide a long QTE2.3.7 environment in a simple procedure to compile the technical documentation, more useful!
Linuxkernelsourcecodeoaming
- 该书主要是描述了linux内核的工作过程，阅读次数，让读者漫游于linux内核中，对理解linux操作系统内核和提高系统编程尤其重要！-The book mainly describes the work of the process of linux kernel, read the number of roaming for readers in the linux kernel, linux operating system kernel to understand and improve
Guinnesslinuxcommand
- 该书主要讲述了linux操作系统的基本命令，不同于别的书，该书的主要优点是深入浅出，非常适合初学者！-The book focuses on the basic commands of linux operating system, unlike other books, the main advantage of the book is easy, very suitable for beginners!
NetRemoteControl
- Net Remote Control- This is no my program but this program I find in internet ... it is for personal use
LQZXJ
- 用c语言编写的哲学家算法模拟 很好很实用 可以方便初学者 掌握-With c language philosophers algorithm simulation is a good beginners can easily master the practical
nextdate
- 关于求解下一天的一个小函数，其中设计了从1912年开始的一直到2050年的计算方式-Solving the next day on a small function, which was designed from the beginning in 1912 until the method for calculating the 2050
4534455RSAvb
- rsa算法C++实现，实现RSA算法，密码强度1024 rsa加密/解密算法实现源码与例子 -rsa algorithm for C++ to achieve, the realization of RSA algorithm, the password strength of 1024 rsa encryption/decryption algorithm and source code examples
RSA56778
- 用VC实现的rsa加密解密算法，本人经过测试，可以 直接使用 生成任意多位和任意多个的大素数，十六进制表示 -VC achieved using rsa encryption and decryption algorithm, I tested and can be directly used to generate any number and any number of large prime numbers, hexadecimal