文件名称:sequenceOfN
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- 上传时间：2012-11-16
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一个正数N，求相加等于N的所有连续的i个数的序列。如N=5，此时只有一个序列2、3.我这个算法的复杂度已经降到根号N，效率很高-A positive number N, seeking the sum is equal to N for all i the number of consecutive sequences. If N = 5, this time there is only one sequence of 2,3. I have the complexity of this algorithm has reached the root of N, efficient
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下载文件列表
sequenceOfN/debug/sequenceOfN.exe
sequenceOfN/sequenceOfN/Debug/BuildLog.htm
sequenceOfN/sequenceOfN/Debug/mt.dep
sequenceOfN/sequenceOfN/Debug/sequenceOfN.exe.intermediate.manifest
sequenceOfN/sequenceOfN/Debug/sequenceOfN.obj
sequenceOfN/sequenceOfN/Debug/vc80.idb
sequenceOfN/sequenceOfN/sequenceOfN.cpp
sequenceOfN/sequenceOfN/sequenceOfN.vcproj
sequenceOfN/sequenceOfN/sequenceOfN.vcproj.DELL-FC02B202D0.dell.user
sequenceOfN/sequenceOfN.ncb
sequenceOfN/sequenceOfN.sln
sequenceOfN/sequenceOfN.suo
sequenceOfN/sequenceOfN/Debug
sequenceOfN/debug
sequenceOfN/sequenceOfN
sequenceOfN
sequenceOfN/sequenceOfN/Debug/BuildLog.htm
sequenceOfN/sequenceOfN/Debug/mt.dep
sequenceOfN/sequenceOfN/Debug/sequenceOfN.exe.intermediate.manifest
sequenceOfN/sequenceOfN/Debug/sequenceOfN.obj
sequenceOfN/sequenceOfN/Debug/vc80.idb
sequenceOfN/sequenceOfN/sequenceOfN.cpp
sequenceOfN/sequenceOfN/sequenceOfN.vcproj
sequenceOfN/sequenceOfN/sequenceOfN.vcproj.DELL-FC02B202D0.dell.user
sequenceOfN/sequenceOfN.ncb
sequenceOfN/sequenceOfN.sln
sequenceOfN/sequenceOfN.suo
sequenceOfN/sequenceOfN/Debug
sequenceOfN/debug
sequenceOfN/sequenceOfN
sequenceOfN
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