资源列表
dgxj
- 用C++实现编译原理的递归下降语法分析 用C++实现编译原理的递归下降语法分析-C compiler to achieve the principle of recursive grammar analysis dropped C compiler to achieve the principle of recursive grammar analysis drop
dijkstra
- D算法MATLAB实现,Dijkatra为主要算法，main函数举例实现-use matlab to make out D
send_col
- send_col in parellel mpi sample
jacobi
- A: aij, 1<= i,j<=n b: 1<=i<=n x0: intial guess, 1<=i<=n tol: tolerance N maximum number of iterations k: number count of iteration Xm(:,k): X in each k iteration-Jacobi s method: In numerical linear algebra, the
Hanoi
- Hanoi game ---programming code
elephant
- 国际象棋中的象在棋盘上总是沿着对角线方向移动。若两个象互相处在对方可以到达的位置上，就可以互相攻击。如下图所示，黑色的格子表示象B1能够到达的位置。象B1和B2间可以互相攻击，但B1和B3间不可以。B2和B3间同样不可以互相攻击。-As in chess on the board is always moving along the diagonal direction. If two like each other in the position of the other party can
Count_number
- 小计算器，可以输入+，-，*，/ 小括号等符号构成的表达式-a calculater
matlab-PLS
- 曲线拟合，函数逼近，预测，偏最小二乘法！-Curve fitting, function approximation, forecast, partial least squares.
egao
- 一个关机恶搞程序，仅供娱乐，其实很简单就用了system函数-A spoof shutdown procedures, for entertainment purposes only, is actually very simple to use system functions
keytest
- 采用外部中断和延时消抖控制按键，能很好地避免按键误动作，实验效果很好-External interrupt and delay debounce control buttons, the button can well avoid malfunction, the experiment works well
fenshu
- 汇编计算一串分数中各个分数段的人数并显示。-The number of each score a bunch of points in the assembly segment is calculated and displayed.
road
- 老王最近承包了某市的造路工程，假设该市有 n 个地点，老王的任务就是连通这 n 个 地点。当然，由于各种原因，连通任意两个地点的代价是不一样的，于是老王请你帮忙设计 出一个算法，计算连通这 n 个地点所用的最小代价。 -Wang recently contracted a city road construction, assume that the city has n locations, Pharaoh s task is communication with the n