资源列表
complex_17a7
- c++ code for complex num
huibian
- 汇编源程序包括文档说明 -Compilation of source code including compilation of source documentation, including documentation
asm
- 提供了汇编语言程序设计题目和代码全解，需要是可以作为参考-Assembly language programming provides the title and code the whole solution is needed as a reference
program
- 汇编语言（王爽著）书上部分习题及例题代码实现。-Assembly language (Wang Shuang was) part of the book exercises and code examples.
calc
- 计算器 有数字按键 + - * / 都有-Public sym, tmp Public Sub Cl_Click() txt = "" Form1.sym = "" Form1.tmp = "" End Sub Public Sub cmd_Click(Index As Integer) If InStr(1, txt, "=") <> 0 Then txt = "" txt = txt & Index End Sub Pub
huibianPPT
- 这个是汇编的电子课件，石老师授课用的 含金量很高-This is a compilation of electronic courseware, stone used for teachers to teach high gold content
3
- 字符串转换和拷贝 Data segment str_a db ‘assembly language is not difficult’ str_b db 40 dup (?) Data ends 请将字符串str_a中的字符转换成大写并拷贝到str_b中。 编写程序，编译连接，用DEBUG运行调试 -String conversion and copying Data segment str_a db ' assembly language is not dif
4
- 编写程序将含有20个数据的数组M分成两个数组：正数组P和负数组N，并分别统计两个数组的个数，显示在屏幕上。 M DB 1,3,-4,…….. ；20个 P DB 20 DUP (?) N DB 20 DUP(?) -Write a program will contain an array of M 20 data into two arrays: an array P and the negative group is N, and two arrays were the nu
ZIFUPIPEI
- 编写程序,实现两个字符串比较。则显示“MATCH”，否则，显示“NOMATCH”-Write a program to achieve two string comparison. Shows the " MATCH" , otherwise, the show " NOMATCH"
IntelCodeTable
- Intel Code Table ,Intel Assembler 80186 and higher
song
- 基于PIC16F877的播放歌曲 两只老虎 源汇编代码 适合初学者学习 推荐-Songs to play on two tigers PIC16F877 assembly code for beginners to learn the source recommended
LED
- 基于PIC877的流水灯汇编源代码 适合初学者 推荐 -PIC877 of water-based light source assembly recommended for beginners