资源列表
hb
- 汇编实现统计字符个数 计算10个0～9之间数字的总和、平均值并统计大于6的数字的个数。 -Calculate the number of characters to achieve statistical compilation of 10 numbers between 0 and 9 sum, average and count the number of numbers greater than 6.
dazi
- 微机原理课程设计_打字练习_汇编课程设计 运行可执行程序testword.exe，出现菜单主界面，按回车键出现由26个字母组成 的乱序行，这时其中任一字母落下，在键盘上敲入该字母，如果输入正确，字母turn red；按ESC键返回主界面；按空格见暂停；按‘E’退出。-Course Design of Microcomputer _ _ typing practice program designed to run compiled executable testword.exe, the mai
binary_addition
- 本实验要求计算X+Y=Z，将结果Z输出到屏幕，其中X=001565A0H，Y=0021B79EH-In this study, the requirements in X+ Y = Z, Z output the results to the screen, where X = 001565A0H, Y = 0021B79EH
decimal_to_binary
- 将ASCII码表示的十进制数转换为二进制数-Will be expressed in decimal ASCII code is converted to binary
c
- 历年二级相关的真题 里面有选择题 填空题 编程题-Two years there Zhenti related multiple choice questions, and so fill in the blank programming
Disam
- Visual C++ 2010写的一个反汇编模块,调用简单,支持Intel指令.-Visual C++ 2010 to write a disassembly module, called a simple and powerful. Support Intel instruction
dianzimiaobiao
- 微机原理课程设计 8253电子秒表实验报告-sdadafafffcafa
decimalconverttoBCD
- 求将缓冲区中存放的000CH的ASCII码转换成十进制数，并将转换结果显示在屏幕上-Stored in the buffer requirements 000CH the ASCII code into decimal, and convert the results displayed on the screen
branch_project
- 程序有顺序、循环、分支和子程序四种结构形式，分支结构的示意图如图5-1所示。本实验要求通过求无符号字节序列中的最大值和最小值来反映分支程序的结构形式。-The order of procedures, loops, branches and subroutines four structure, branch structure diagram in Figure 5-1. This experiment requires an unsigned byte sequence by calcula
heximalASC_convert_to_decimal
- 将十六进制数的ASCII码转换为十进制数-Hexadecimal numbers to decimal ASCII code conversion
loop_project_design
- 本实验要求通过求某数据区内负数的个数来表现循环程序的结构形式。要求实验程序在数据区中存放一组数据，为统计负数的个数，逐个判断区内的数据，然后将所有数据中凡是符号位为1的数据的个数累加起来，即得到区内所包含负数的个数-This experiment requires a data region by calculating the number of negative performance cycle to structure the program. Experimental procedur
xunzai.com
- 汇编语言的课程课件 希望大家能够喜欢，也希望大家上传更多的源代码 希望大家继续支持pudn网-Assembly language courseware hope you will like, I hope you upload more code hope you will continue to support pudn Network