资源列表
1101xulieqi
- 一个简单的1101检测序列设计源程序，VHDL编程实现-1101 Detection of a simple sequence of source code, VHDL programming
chuanrubingchu
- 串入并出序列源程序，VHDL语言实现编程，程序比较简单，适应初学者-String into and out of sequence source code, VHDL programming language implementation, the program is relatively simple to adapt for beginners
ch13_ex13_4
- The detection of faces made easy
5
- 一个猜单词的小游戏wordZ。该程序将从一个字典中随机地选择一个单词，并用’－’字符告诉用户该单词有几个字母。用户每次输入一个字母后，程序判断该字母是否在该单词中，如果有则显示该单词中所有该字母，否则提示没有猜中。用户可以最多有8次猜测的机会（重复输入的字母不计入在内。）。如果用户在最大的猜测机会内猜中了该单词，则该次游戏用户胜利，否则用户失败。-A guess word game wordZ. The program will randomly choose a dictionary, a w
ourdev_478346
- 电动车控制器原理图,如果其他会员下载一次您上传的源码-DDB
abcd
- 电脑高手必备的知识 ， 让你轻松成为高手！不看会后悔啊 -Computer expert knowledge necessary to enable you to easily become a master! Do not look at any regrets ah
subtraction
- This aassembly program to subtraction. the systematic decomposition of the process of subtracting two integers in registers R1 and R2.-This is aassembly program to subtraction. the systematic decomposition of the process of subtracting two intege
compare
- LC3 program that compares two numbers in R2 and R3 and puts the larger number in R1. If the two numbers are equal, then R1 is set equal to 0.
or
- The LC-3 program to perform the OR of the contents of R1 and R2 and puts the result in R3.
sum
- LC-3 program to calculate the sum of all the 8-bit 2’s complement values in a packed array of N elements. With N elements in the packed array, we require N/2 memory location. For this assignment, we will assume N is even. Your SUM will be stored in o
IntergerDivision
- LC-3 assembly language machine code to test and solve the Problem of Integer Divide and Modulo.
asmd
- 编写一程序，用以判断BUF1和BUF2两个等长度的数据区中数据是否相同。相同则使FLAG单元置0，否则置-1。-Write a program used to determine BUF1 and BUF2 two data areas such as the length of the data are the same. FLAG unit makes the same set 0, otherwise set-1.