资源列表
paixu
- 从首地址为1000H开始存放10个数,要求设计程序将这些数由小到大排序,排序后的数仍放在原地址处。-Starting from the first address 1000H store the number 10 to require the design process to sort these the number of small to large, sort after a few still on the original address.
copy
- 题目实现DOS中的COPY命令。可首先打开源文件和目的文件,其次顺序读取源文件每个字节赋给目的文件对应位置,源文件读完时,目的文件也自然拷贝成功。-Title achieve the DOS in the COPY command. Be the first to open the source file and destination file, followed by sequential reads the source file is assigned to the purpose of
bright
- PIC16c57 Bright embedded control module模拟串口通信部分-PIC16c57 Bright embedded control module
zhongduan
- 中断程序 实现统计男女生个数 0代表男生 1代表女生 键盘输入 -Interrupt program for boys and girls to achieve statistical number of 0 for boys and girls on behalf of a keyboard input
count
- 实现统计男女生个数 0代表男生 1代表女生 键盘输入 中断调用 -Interrupt program for boys and girls to achieve statistical number of 0 for boys and girls on behalf of a keyboard input
clockzhongduan
- 时钟中断历程 可以下下来参考一下 很不错的程序 适合于汇编初学者参考-Process can break down the clock, under the procedures refer to very good reference for beginners compilation
hong_macro
- 宏汇编 可以下下来参考一下 很不错的程序 适合于汇编初学者参考-Macro Assembler can make a very good reference down the procedure for compilation of reference for beginners
huibianshiyanzhidao
- 汇编程序指导,具体上机步骤,以及详细实例- Instruction of IBM-PC project code help
yuesefu
- 编号为1,2… n的n个人按顺时针方向围坐一圈,每人持有一个密码(正整数)。一开始任选一个正整数作为报数的上限值m,从第一个人开始按顺时针方向自1开始顺序报数,报到m时停止报数,报m的人出列,将他的密码作为新的m值,从他的顺时针方向上的下一个开始重新从1报数,如此下去,直至所有人全部出列为止,设计一个程序求出出列顺序。 (1)利用单循环链表作为存储结构模拟此过程; (2)键盘输入总人数、初始报数上限值m及各人密码; (3)按照出列顺序输出各人的编号。-Numbered
huibianyuyanchengxudaima
- 汇编语言做的微机原理课程设计案例,共有27个,其中有闰年判断,产生随机数,计算平台长度,打字练习,显示系统时间,简易文本编辑器-The computer assembly language to curriculum design principles of case, a total of 27, including leap year judged to produce random numbers, computing platform length, typing practice, d
ghjk
- 十进制加法器 示范的的游侠的序号的的剑客骄傲 到家了库文件发动机阿拉斯加法律-Decimal adder demonstration of the Ranger of the serial number of the swordsman proud home of the library file engine Alaska law
1
- 基带传输常用码的编码解码MATLAB方法 -baseband transmission
