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Philosopher
- 哲学家就餐问题 操作系统模拟实验解答,详细具体-Dining philosophers problem
philosopher.tar
- 用C语言实现了经典的哲学家吃饭问题。使用了信号量机制。-Dinning philosopher s problem implemented in C
philosophers
- linux下哲学家用餐的经典问题,内含makeifile和主函数源代码-Under the classic dining philosophers linux problem and the main function contains the source code makeifile
thread
- 实验总体要求,使用MFC相关的功能函数来模拟经典进程互斥和同步问题 生产者和消费者 读者和写者 哲学家就餐问题-The general requirements of experiments, the use of MFC function to simulate the functions related to the classical problem of mutual exclusion and synchronization producers and consumers,
eating
- 哲学家进餐问题,在各种编程语言中都会遇到,尤其是在WinForm编程中.-Dining philosophers problem, in a variety of programming languages ??are encountered, especially in the WinForm programming.
main
- 柔性机械制造系统死锁的防止方法仿真哲学家就餐问题的java程序研究 -Flexible Manufacturing Systems deadlock prevention method for simulation of the dining philosophers problem of java program
OS4
- 模拟哲学家就餐问题:设置5个子线程模拟5个哲学家,设置5个互斥区为筷子。输出各个哲学家的状态,如果在就餐,则同时输出他所使用的左右筷子序号。-Simulation of the dining philosophers problem: Set 5 5 sub-thread simulation philosopher, set five mutually exclusive area for chopsticks. The state of the output of each philosop
a7b01aa086f0
- 哲学家算法的C++实现,不是很强大, 很适合初学者。-Philosophers algorithm C++ implementation is not very strong, very suitable for beginners.
DINING
- 网络编程代码,网络编程中能用到的例子--哲学家进餐问题-Network programming code, network programming can be used to the example- dining philosophers problem
DiningPhils
- 五位哲学家吃面条,只有五根筷子。每个人必须用一双筷子才能吃面条。-Five philosophers eat noodles, only five chopsticks. Each person must use a pair of chopsticks to eat noodles.
zxuejiajiucanwenti
- 哲学家就餐问题:很好解决死锁问题,是操作系统课程设计的一个范例-Dining philosophers problem: a good solution to the deadlock problem, the operating system is an example of curriculum design
dining
- 哲学家进餐代码 附加可执行文件 哲学家进餐代码 附加可执行文件-Dining philosophers code attached executable file attached executable code dining philosophers
java
- 实现哲学家进餐问题,一共有五位哲学家在思考或者进餐,解决进程同步的问题-Dining philosophers problem to achieve
ZEXUEJIAJIUCAN
- 嵌入式操作系统实验实验用例程序源代码:一个关于哲学家就餐的源程序。-English of UCOS.The program of ZEXUEJIAJIUCAN.
Dining-philosophers-problem
- 哲学家就餐问题 实现5个哲学家5支筷子的就餐问题涉及到AND型信号量,线程的阻塞唤醒切换功能-Dining philosophers problem to achieve five dining philosophers five chopsticks issues related to the AND-type semaphore, blocking thread switching wake
duodao
- 多道批处理系统 用于作业的进程调度 修改哲学家就餐问题-Multi-channel system for batch process scheduling jobs to modify the dining philosophers problem
duodao2
- 多道批处理系统 用于作业的进程调度 修改哲学家就餐问题-Multi-channel system for batch process scheduling jobs to modify the dining philosophers problem
zhexuejia
- 多进程/线程编程:哲学家问题。 设置进程/线程,描述哲学家 ; 随机启动哲学家 ; 显示进程/线程执行状态; 随着线程的执行,更新显示; 编写正确的哲学家程序,设法延迟线程的执行,使之出现死锁; 编写正确的哲学家程序,保证不出现死锁;-philosophers problem
dining
- 说明:本程序是操作系统中比较典型的线程同步算法中的哲学家进餐问题,为防止死锁,采取了两个条件(筷子空闲)同时满足时再允许进餐的办法来解决。-Note: This procedure is typical of the operating system thread synchronization algorithm dining philosophers problem, in order to prevent deadlock, has taken two conditions (free c
philosopher
- 哲学家问题,解决进程死锁和恢复,进程调度。 多线程任务。-Philosophers problem, solve the deadlock and restore processes, process scheduling. Multithreaded.