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RSA1 用RSA算法实现加解密的功能
- 用RSA算法实现加解密的功能，可支持128-2048位，RELEASE版本，无问题。还有可支持大数运算的计算功能-RSA encryption algorithm with the functionality to support 128-2048 bit, RELEASE version, no problem. There can support large numbers of computing operations
random-inc
- 用c语言编写的产生正态随机数的源代码: 算法一产生12个（0，1）平均分布的随机函数，用大数定理可以模拟出正态分布。 算法二用到了数学中的雅可比变换，直接生成正态分布，但此算法在计算很大规模的数时 会出现溢出错误。-With the c language normal random number generation source code: Algorithm 1 produces 12 (0,1) the average distribution of the rand
test
- Java 大数解决计算精度问题，比如2.0-1.1=0.89999999999的问题-Java large numbers to solve computational accuracy problems, such as 2.0-1.1 = 0.89999999999 problems
momi
- 大数的模幂算法(GUI)，用密码学课本中的算法，快速、高效。计算(x的r次方) mod p 的值-Large numbers of modular exponentiation algorithm (GUI), used cryptography algorithm textbooks, fast and efficient. Calculation of (x of the r-th power) mod p value
2008.12.1
- 计算大数的阶乘，用的链表和数组的方法。 用于学习-Calculation of the factorial of large numbers, using the linked list and array method. For learning
dashuxiangcheng
- 计算大数阶乘,方便处理大于64位整型数值的相乘-Factorial calculation of large numbers, facilitate the processing of more than 64-bit integer value multiplied
0062
- 用DEPHI实现计算最大公约数，最大公约数是即能够整除各数的最大数。-Calculated using Delphi to achieve the common denominator, the common denominator is the number that is divisible to the greatest number.
afanty_Bigint
- 这是关于大数运算的程序，用vc开打的。可以计算加减乘除。-This is the operator on the large numbers of procedures, with the start vc. Calculation can be calculated.
rsa
- 1) 找出两个相异的大素数P和Q，令N＝P×Q，M＝（P－1）（Q－1）。 2) 找出与M互素的大数E，用欧氏算法计算出大数D，使D×E≡1 MOD M。 3) 丢弃P和Q，公开E，D和N。E和N即加密密钥，D和N即解密密钥。 -1) to identify two different large prime numbers P and Q, so N = P × Q, M = (P-1) (Q-1). 2) to identify and M large numbers cop
rsajiamiyunli
- 加密的步骤 1) 计算N的有效位数tn（以字节数计），将最高位的零忽略掉，令tn1＝tn－1。比如N＝0x012A05，其有效位数tn＝5，tn1＝4。 2) 将明文数据A分割成tn1位（以字节数计）的块，每块看成一个大数，块数记为bn。从而，保证了每块都小于N。 3) 对A的每一块Ai进行Bi＝Ai^E MOD N运算。Bi就是密文数据的一块，将所有密文块合并起来，就得到了密文数据B。 -Encryption step 1) calculating the media
ajiab
- 计算两个可达2000位长的大数之和，输入两个大数，显示整个加法-apulsb
KeyGen
- 使用miracl大数库实现RSA算法，根据用户名计算相应序列号。-The use of large numbers miracl Treasury realize RSA algorithm, were calculated based on user corresponding serial number.
SDL_1_1_alpha
- 简单的C++计算库.其中实现了矩阵运算,大数运算.矩阵处理中使用lazy calculate,并且封装常见算法,可以将普通matlab程序用SDL改写.-Easy calculation of the C++ library. One of implementation of matrix operations, computation of large numbers. Matrix deal with the use of lazy calculate, and packaging comm
catalan
- catalan大数的计算，用字符串实现，效率不太高-the calculation of catalan
076
- 计算高次方数的尾数，大数方的计算，C语言实现，TC运行。-Calculating the number of high-power mantissa, the calculation of large numbers side, C language implementation, TC run.
D
- 计算两个100位大数的除法，结果保留100位小数-Calculation of two of the division of large numbers 100, 100 to retain a small number of results
DaShuJieChen
- 将一个数进行阶乘结果会是一个很大的数，在c语言里double型也最大只能存一个两位数的整数的阶乘。本算法是对大数进行阶乘计算。-Factorial of a number of results will be carried out is a very large number of languages in the c-type double can only keep the largest of a double-digit integer number. This algorithm i
nc.jar
- Java 数值计算库 数列求和算法、求解方程的根、插值法和近似法、 数值积分、求解微分方程、矩阵运算及其它一些有趣的东西， 比如：大数、素数算法、PI、分形-Java Number Cruncher
bignum
- 使用链表实现大数的阶乘运算，如10000！的计算，速度还可以-BigNum
calculator
- 简单的计算器，用于大数的计算。位数没有限制。-simple large number calculator