搜索资源列表
Knapsack
- 我自己做的一个0-1背包问题程序 用回溯法 做的 望大家分享 请指正-I own a 0-1 knapsack problem with retroactive law procedures do hope to share, please correct me
beibao
- 0-1背包问题:输入两个整数n和m,从数列1,2,3....n中随意取几个数,使得其和等于m,求所有组合-0-1 knapsack problem: Enter the two integers n and m, from a series of 1,2,3 .... n grab a few numbers and make it equal to m, for all combinations
01beibao3
- 0-1背包问题 将计算出的装入背包物品的最大价值和最优装入方案输出。第一行输出为:Optimal value is-0-1 knapsack problem will be calculated into the knapsack to maximize the value of goods and optimum output load program. The first line of output: Optimal value is
Knapsack
- 0-1背包问题, 0-1背包问题 Version 1.0 2008-10-28-0-1 knapsack problem, 0-1 knapsack problem Version 1.02008-10-28
exp3
- 著名的0-1背包问题 C++实现 矩阵显示过程-Well-known 0-1 knapsack problem C++ Realization process matrix display
c
- 用回溯法求解0—1背包问题,并输出问题的最优解。-Retrospective method with 0-1 knapsack problem, and output the optimal solution of the problem.
report+of+Algorithm
- 算法设计的实验报告 包括Bottom-Up Merge Sorting算法、插入排序算法Heaps的创建堆、堆排序算法、按秩合并算法以及带路径压缩算法、实现查找第K小元素算法、实现快速排序算法、实现平面内最接近点对算法、实现最长公共子序列算法、实现矩阵链相乘算法、实现0/1背包问题算法、实现Dijistra’s算法、Prim算法、Kruskal算法、文件压缩算法-Experimental Algorithm Design Report including Bottom-Up Merge So
BeiBao1
- 动态规划算法求解0-1背包问题,动态规划算法knapsack求最优值-Dynamic programming algorithm for solving 0-1 knapsack problem, dynamic programming algorithm for optimal value knapsack
bag
- 分支限界法解决0/1背包问题,用c++的优先队列方法-Branch and bound method to solve 0/1 knapsack problem, using c++ Priority queue method
simulatedannealingalgorithm
- 关于模拟退火算法的书籍,以及在0-1背包问题、旅行商问题上的实现-a book about simulated annealing algorithm
Based
- 基于遗传算法的0-1背包问题的求解,可进一步另深对遗传算法理解,学习算法分析与设计的可以-Based on Genetic Algorithm for Solving 0-1 Knapsack Problem
1108
- 在0 / 1背包问题中,需对容量为c 的背包进行装载。从n 个物品中选取装入背包的物品,每件物品i 的重量为wi ,价值为pi 。对于可行的背包装载,背包中物品的总重量不能超过背包的容量,最佳装载是指所装入的物品价值最高,即n ?i=1pi xi 取得最大值。约束条件为n ?i =1wi xi≤c 和xi?[ 0 , 1 ] [ 1≤i≤n]。-At 0/1 knapsack problem, there is a need for a capacity of c for the loaded
d
- 1. 0-1背包问题 在0 / 1背包问题中,需对容量为c 的背包进行装载。从n 个物品中选取装入背包的物品,每件物品i 的重量为wi ,价值为pi 。对于可行的背包装载,背包中物品的总重量不能超过背包的容量,最佳装载是指所装入的物品价值最高 -1. 0-1 knapsack problem at 0/1 knapsack problem, there is a need for a capacity of c for the loaded backpack. N items from
i-ant
- 采用了基本的蚁群算法来求解0-1背包问题,该算法不仅可以对0-1背包问题进行求解,还可以对多维背包问题进行求解。-Using the basic ant colony algorithm to solve the 0-1 knapsack problem, the algorithm not only for the 0-1 knapsack problem can be solved, but also multi-dimensional knapsack problem can be sol
01beibaowenti
- 0-1背包问题的源码,包括问题描述,算法思想-01beibaowenti
beibao
- 对几种背包问的分析与解释,主要包干,0/1背包问题,完全背包问题-failed to translate
Dynamic01
- 使用C++编写的动态规划--0-1背包问题。-The use of C++, prepared by dynamic programming- 0-1 knapsack problem.
tracking01
- 采用回溯法解决0-1背包问题,验证是否能获得最优解.-Retrospective method used to solve 0-1 knapsack problem, verify whether he can be the optimal solution.
ACO_0_1_bag
- 蚁群算法解0-1背包问题 内附测试文件 解的质量一般叫好,但是背包数增加时,耗时较长-Ant Colony Algorithm for 0-1 Knapsack Problem solution document containing test the quality of the general good, but the increase in the number of backpack, the longer time-consuming
0-1bag
- 解决0/1背包问题 : 给定一定容量的一个背包,要求放入的货物价值最大(每个货物有固定的容量和价值)-Solve the 0/1 knapsack problem: given a knapsack of a certain capacity, the requirements placed the greatest value of the goods (one for each cargo capacity and a fixed value)