搜索资源列表
simpson_RMS
- 在uVision环境下用C编程,用辛普森算法计算有效值-In uVision environment with C Programming with OJ Simpson algorithm RMS
NUAA_1063_report
- NUAA ACM OJ 1063 矩阵算法-NUAA ACM OJ 1063 Matrix Algorithm
q
- OJ上的常见问题及解答-OJ common questions and answers on the
Billiards
- oj平台上的题目源代码,非常有用的啊。另外还可以直接AC-oj subject of the source code on the platform, very useful ah. AC can also
code
- OJ平台上的10道题的源码,可以全部通过,并且代码最简单。可以直接下载-OJ platform 10 questions of the source, you can all pass, and the code simple. Direct download
Sicily.1763
- 中山大学OJ(Sicily)题目1763的解题报告,使用DFS算法。-Sun Yat-sen OJ (Sicily) problem-solving questions 1763 report, the use of DFS algorithm.
dp
- oj题目源代码,用于备份和测试 oj题目源代码,用于备份和测试-oj subject source code, used to back up the source code and test questions oj, oj subject for backup and testing source code for backup and testing
DP
- 有关动态规划DP的一些资料,包括两个学习动态规划的PPT,以及OJ的一些题目及解题代码,并附背包问题求解。-Dynamic programming DP on some of the information, including the two learning dynamic programming PPT, and OJ and solving some of the topics the code, together with Knapsack Problem.
HDOJP1871P-P2000
- 杭电OJ的源码1871-2000,有的题目会用多种方法解决-Hang power source 1871-2000 OJ, and some will use various methods to resolve questions
program1.2
- 本系统是一个学生成绩管理系统,采用C语言编写的。通俗易懂,便于C语言入门学习。-jfoi jewoifw jfwio fei fjei ieji jie jie oj of low so dcio ao
USB
- USB接口驱动程序,请看看,应该有用处地-USB siu owoi jd oj ep ok l fjfo wejf klsdf kojf soejfs psodfjsod
translation
- 翻译问题解题报告 OJ刷题必备 详解细致说明-Report translation problem solving essential questions Detailed OJ detailed descr iption of the brush
Eight-Digital-A_star
- 八数码A*算法,浙大OJ已AC 内含序列合法判定以及A*搜索思路-Eight Digital A* algorithm, Zhejiang University has AC OJ
Algorithm-for-test-data
- 算法考试资料,oj刷题的好帮手,附常用代码和模板-Algorithm test data, oj brush question is a good helper, with a common code and templates
hoj
- 杭州电子科技大学OJ 部分代码。新手必备-some codes about hOJ
bolanjisuanqi
- 背景 以下是几个标准的表达式: 5 * 2 + -3 5 * (2 + -3) 5 + ((-4 * -5) + (((5 + (6 - 2)) * 7 + ((4 + 2) * (3 - 1)))) 与之等价的波兰表达式为 + * 5 2 -3 * 5 + 2 -3 + 5 + * -4 -5 + * + 5 - 6 2 7 * + 4 2 - 3 1 在普通的表达式中,符号是位于运算对象之间的,而在波兰表达式中,运算符号位于参
chicken-counting
- 百鸡问题 一个小程序 OJ上的1125 代码很精简的计算-chicken counting
sicily-1150-1151
- 实现西西里OJ题目中1150和1150模板的转换,-To achieve the conversion of templates
notes
- 很经典的ACM试题解答,习题练习解答;在oj中几乎都有。-ACM is the classic answer questions, practice exercises to answer almost all the oj.
Uva
- UVA题目的AC代码: 414,439,489,490,657,11941-UVA OJ problem solution for: 414,439,489,490,657,11941