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Wangmeng_3281411350
- 哲学家问题演示 不会哦，副教授法是发生副教授法寄生蜂机发射机发生发生棵-philosopher Oh no demonstrated problem, law professor, associate professor of law occurred parasitoids machine transmitter happened happened with every tr
Philosopher（new）
- 这是一道经典的线程同步问题——哲学家吃饭问题。这里结合了win32使得这个问题可视化了-This is a classic thread synchronization -- philosopher food problem. Win32 here combination of this makes the issue of visualization
threadphilosopher
- 利用线程方案实现实现哲学家问题.设置五个信号量代表五把叉子，初使值均为1，表示5把叉子均可以取，设置五个线程代表5个哲学家，其值分别为0～4，规定奇数号的哲学家先拿起他左边的叉子,然后再去拿他右边的叉子 而偶数号的哲学家则相反.按此规定,将是1,2号哲学家竞争1号叉子,3,4号哲学家竞争3号叉子.即五个哲学家都竞争奇数号叉子,获得后,再去竞争偶数号叉子,最后总会有一个哲学家能获得两支叉子而进餐。而申请不到的哲学家进入阻塞等待队列，根FIFO原则，则先申请的哲学家会较先可以吃饭，因此不会出现饿死的
DINING
- 哲学家吃饭的好东东，一定要好好研究研究哦!-philosopher Wanton good meal, we must carefully study a Oh!
vc++eatingcode
- 非常经典的哲学家进餐问题（与进程有关）有三个哲学家围着一张桌子，桌子上摆着一碗通心粉；桌子上有且只有三支筷子，且每只筷子摆放在每两个哲学家中间；哲学家必须得到两支筷子才能吃饭，否则就处于思考状态；每个哲学家取筷子必须先取得左边，而后取右边的。 -very classic philosophers dining (with the process) is a three philosophers around the table, on the table untouched bowl of
philosopher
- 用线程解决“N个哲学家”问题 1、目的： 学习线程的编程和同步
philosopher
- 哲学家进餐问题是荷兰学者Dijkstra 提出的经典问题之一,它是一个信号量机制问题的应用,在操作系统文化史上具有非常重要的地位。对该问题的剖析有助于学生深刻地理解计算机系统中的资源共享、进程同步、死锁等问题,并能熟练地应用信号量来解决生活中的控制流程,即将生活中的控制流程用形式化的方式表达出来。-Dining philosophers problem is that the Dutch scholars Dijkstra classic one of the issues raised, it
operation
- c++实现的进程线程问题，包括父子进程，哲学家进餐问题等等.-c++ implementation of the process of threading issues, including his son process, the philosopher eating problems, and so.
DiningPhilosophers
- 六个哲学家就餐问题,体验进程(线程)和死锁的问题.本实验设计个哲学家共享一个相同的线程,既完成线程同步,又预防死锁发生.-6 dining philosophers problem, experience the process (thread) and deadlock issues. The experimental design a philosopher share a similar thread, both complete thread synchronization, but a
philosophersproblem
- 利用多线程技术实现生产者－消费者问题以及n个哲学家就餐问题，其中生产者或消费者或哲学家用不同线程实现-Using multi-threading technology producer- consumer issues and the n-dining philosophers problem, in which the producer or consumer or a philosopher to achieve a different thread
philosopher
- 哲学家问题，解决进程死锁和恢复，进程调度。 多线程任务。-Philosophers problem, solve the deadlock and restore processes, process scheduling. Multithreaded.
Philosopher
- 进程（线程）同步及死锁--哲学家进餐问题-Philosopher problem
Philosopher(Optional)
- 哲学家问题，也就是消费者-制造者问题AVR32EVK1100为硬件。C语言编程，FreeROTS为API.-Philosophers problem, that is, consumers- the problem AVR32EVK1100 the hardware manufacturer. C language programming, FreeROTS for the API.
chengxu
- 进程互斥进程同步 哲学家有N个，也定全体到达后开始讨论：在讨论的间隙哲学家进餐，每人进餐时都需使用刀、叉各一把，所有哲学家刀和叉都拿到后才能进餐。哲学家的人数、餐桌上的布置自行设定，实现刀和叉的互斥使用算法的程序实现。-The philosopher N, also all arrived to begin to discuss: in the discussion of the gap the dining philosophers, each table needs to use kni
Philosopher-dine
- 简单的哲学家进餐问题解决方案，使用互斥线程-Simple solutions to dining philosophers problem, using mutually exclusive threads
philosopher
- 使用多线程来解决哲学家就餐问题的源代-To use multiple threads to solve the source code for the dining philosophers problem
zhexuejia-
- 哲学家算法uc_os实现,可以直接运行,不需要额外配置环境-Uc_os philosopher algorithm to achieve