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jsq
- 科学计算器功能，有加减乘除，平方开方求根，角度弧度计算，2、8、10、16进制间的转换。-Scientific calculator function, calculation, square roots prescr iption, angle radian calculation, 2,8,10,16 between hexadecimal conversion.
zxmsammyjsq
- 科学计算器功能，有加减乘除，平方开方求根，角度弧度计算，2、8、10、16进制间的转换。-Scientific calculator function, calculation, square roots prescr iption, angle radian calculation, 2,8,10,16 between hexadecimal conversion.
book_1
- 孙子兵法，菜根潭，忍经，反经，不窗幽记，围炉夜话，鬼谷子等古籍，PDF格式，-The Art of War, Tam roots, and tolerance by anti-economic, not a window Youtong mind that Irori夜话, Gui Guzi, such as books, PDF format,
badaqishu
- 孙子兵法，菜根潭，忍经，反经，不窗幽记，围炉夜话，鬼谷子等古籍，PDF格式，-The Art of War, Tam roots, and tolerance by anti-economic, not a window Youtong mind that Irori夜话, Gui Guzi, such as books, PDF format,
Programacion_y_metodos_numericos
- Topics Practices: Programming and Numerical Methods Practice 1: Introduction to C Practice 2: Cycles and functions First part cycles Part Two: Roles Practice 3 - Floating point arithmetic Practice 4 - Search for roots of funct
Real-roots-of-equations-of-higher
- 本文根据STURM定理设计了一个算法按这一算法编写了一个求高次方程所有实根近似值的C语言程序. -STURM theorem in this article in accordance with an algorithm designed by this method for the preparation of a high approximation of real roots of all equations of the C language program.
libsvm-2.89
- SVM, Support Vector Machine , 簡而言之它是個起源跟類神經網路有點像的東西， 不過現今最常拿來就是做分類 (classification)。 也就是說，如果我有一堆已經分好類的東西 （可是分類的依據是未知的！） ，那當收到新的東西時， SVM 可以預測 (predict) 新的資料要分到哪一堆去。 -SVM, Support Vector Machine , is something that has similar roots with neural network
DAG
- 若在DGA图中存在一个顶点r，在r和图中所有其他顶点之间均存在由r出发的有向路径，则称该DAG图有根，试编写求DAG图的根的算法。 -If there is a DGA map vertex r, in r and the graph all the other vertices exist in between the departure from the r to the path are said to have roots in the DAG plans, test plans p
2
- 方程求根的数值试验，利用Newton迭代法，求所给出的方程的跟。-Equation Roots of numerical experiments, using Newton iteration method, find the equation with the given.
mathAndProgramming
- 宇宙是用数学语言写成的，一切程序的运行归根于数学，现在介绍几个程序与数学的例子-The universe is written in mathematical language, all programs run return to their roots in mathematics, will now describe a few examples of procedures and mathematical
solvingequation
- 用因式分解的方法求解方程ax^n+bx^(n-1)+ ……+cx+k的根。课程设计-Using the factorization method of solving equation ax ^ n+ bx ^ (n-1)+ ... ...+ cx+ k roots. Curriculum
boot
- 数根 数也有根吗？有！数根就是把一个数的各个数位上的值相加，直到得到一个一位数为止。请你编写一个程序来计算任意数N（0≤N≤1000000000000）的根。 输入： 输入有多个案例。每一个案例为一行，每行只有一个整数N。当输入的N是-1时，输入结束。 输出： 每一个案例输出一行。每行只有一个数字，就是N对应的数根。 Sample input 39 -1 Sample output 3-Number of root number als
fcqg
- matlab方程求根程序，里面包括了常用的matlab方程求根的程序，包括手写的和matlab自还的函数。-matlab equation Roots program, which includes the commonly used procedure for finding roots of equations matlab, including handwritten and self is also a function of matlab.
fangchengqiugen
- 这是用MATLAB实现方程的求根问题，有贝努力法等十几种算法，具体的代码都已给出。-This is achieved using MATLAB problems finding roots of equations, there are a dozen Bernoulli law algorithms have been given a specific code.
matlab
- clear num=[0,0,10] den=[1,2,10] p=roots(den) [u,w]=solve( w^2=10 , 2*w*u=2 , u,w ) [y,x,t]=step(num,den) plot(t,y) [yss,n]=max(y) finalvalue=dcgain(num,den) percentovershoot=100*(yss-finalvalue)/finalvalue timetopeak=t(n
newton
- Newto迭代非线性方程的根，可以求解多根情况-Newto iterative roots of nonlinear equations, can solve the situation of multiple
SeekdefiniteintegralandtheRootsoffunctioniteration
- 求定积分函数和迭代求根函数，都是从网上下来之后，自己改了一些，能在vc中运行的。-Seek definite integral function and the Roots of function iteration, are down from the Internet after its changed some, running in vc.
GetEquationRoot
- 一元二次求根，考虑得比较全面。比如方程有两个不同的实根，两个相同的实根，两个虚根，方程退化成一元一次方程，以及无解的情况。最后根的显示也使用一个小小的技巧 小程序不复杂，但是未必每个人第一次都能做的很完善 -Quadratic root finding, may be considered more comprehensive. Such as the equation has two different real roots, two identical real roots, two ima
MCI-core---working-with-square-roots
- MCI core - working with square roots
find-roots
- MATLAB 数值求根程序，用二分法求任意函数的跟-find roots