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背包算法
- 高级算法中的背包问题求解，算法简便高效，主要解决动态规划0-1背包问题-senior algorithm to solve the knapsack problem, the algorithm is simple and efficient, dynamic programming solution 0-1 knapsack problem
贪婪算法解决背包
- 运用贪婪算法能够很好解决0/1背包问题，这是我编的一个小程序，运行过很好。-greedy algorithm can be used to solve a very good 0 / 1 knapsack problem, this is my part of a small program running very good.
背包问题的两种算法实现
- 本例编程实现背包问题的递归和非递归算法，让你彻底了解这种算法-the cases Programming knapsack problem of recursive and non - recursive algorithm, so you thoroughly understand this algorithm
01背包问题
- 采用分枝限界法解决0/1背包问题! 本人上机实习作业,通过老师验收,合格! 针对部分上机实习的同学可以来下~-used Branch and Bound France 0 / 1 knapsack problem! I practice on the machine operations, acceptance by the teachers, qualified! In view of the attachment on the machine for students to the
背包问题的解决
- 背包问题的解决 :给定一个超递增序列和一个背包的容量,然后在超递增序列中选(只能选一次)或不选每一个数值,使得选中...解决0/1背包问题的方法有多种,最常用的有贪婪法和动态规划法。
0-1背包的回溯算法
- 回溯法解决0-1背包问题-Backtracking 0-1 knapsack problem solving
0-1背包的动态规划算法
- 动态规划0-1背包问题-Dynamic Programming 0-1 knapsack problem
0-1背问题
- 0-1背包问题 可以提供在背包方面遇到问题的学生或者有需要的人.-0-1 knapsack problem can provide a backpack problems encountered students or those who are in need.
背包问题(动态规划递归算法）的vc程序
- 用动态规划算法中的递归法求解背包问题的vc++6程序，已通过测试
0-1背包问题
- 动态规划法解决0-1背包问题
01beibao.rar
- 01背包问题，里面有四种算法，分别为动态规划，分支限定发，回溯法和谈新算法！,01 knapsack problem, there are four kinds of algorithms, dynamic programming, respectively, branch limit hair, the new algorithm backtracking peace!
fenzhixianjie
- 0/1背包问题的优先队列式分支限界算法程序-0/1 knapsack problem the priority queue-type branch and bound algorithm procedure
0-1Knapsack.problem
- Knapsack problemnew01背包问题（动态规划） 01背包实验报告-Knapsack problemnew01 knapsack problem (dynamic programming) 01 backpack Experimental Report
beibao
- 背包问题，可以解决最短路径问题，或优化问题-Knapsack problem, the shortest path problem can be solved, or optimization problems
Algorithms
- 算法导论上机作业java实现，主要有背包问题，八皇后问题，递归等。-Introduction to the machine operation algorithm java to achieve, there are knapsack problem, the eight queen problem, recursive and so on.
pack
- 一个简化的背包问题：一个背包能装总重量为 T，现有 n 个物件，其重量分别为（W1、W2、…、Wn）。问能否从这 n 个物件中挑选若干个物件放入背包中，使其总重量正好为 T ？若有解则给出全部解，否则输出无解。-A simplified knapsack problem: a backpack can hold a total weight for the T, the existing n-object, its weight, respectively (W1, W2, ..., Wn).
01knapsackMFC
- 01背包问题演示程序 用mfc实现01背包问题的dp算法-01 knapsack problem with mfc demo program to achieve 01 knapsack problem algorithm dp
Fac3_9
- //0-1背包问题动态规划解法，原自王晓东算法设计，该程序已调通-//0-1 knapsack problem dynamic programming method, the original algorithm since Xiaodong design, the program has been transferred Qualcomm
0-1knapsack_problem
- 0/1背包问题：给定n种物品和一个容量为C的背包，物品i的重量是wi，其价值为vi，0/1背包问题是如何选择装入背包的物品（物品不可分割），使得装入背包中物品的总价值最大?回溯法解决0/1背包问题-0/1 knapsack problem: given n types of items and a knapsack of capacity C, the weight of item i is wi, the value of vi, 0/1 knapsack problem is how to
beibao5
- /* 背包问题 问题定义： 有一个背包重量是T，有n件物品，重量分别是W0,W1...Wn-1 问能否从这n件物品中选择若干件放入背包中使其重量之和正好为T */(Tipcal package problem)