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采用分枝限界法解决0/1背包问题!
本人上机实习作业,通过老师验收,合格!
针对部分上机实习的同学可以来下~-used Branch and Bound France 0 / 1 knapsack problem! I practice on the machine operations, acceptance by the teachers, qualified! In view of the attachment on the machine for students to the
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背包问题优先队列分枝限界算法
所谓的背包问题，可以描述如下：一个小偷打劫一个保险箱，发现柜子里有N类不同大小与价值的物品，但小偷只有一个容积为M的背包来装东西，背包问题就是要找出一个小偷选择所偷物品的组合，以使偷走的物品总价值最大。这个问题的求解有很多种方法，本程序使用分枝限界法求解。-knapsack problem Branch and Bound priority queue algorithm called knapsack problem can be described as f
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该程序用动态规划解决经典的背包问题,虽然它的效率与分支定界法比起来,还是有一定的差距,但它的简洁性却是无与伦比的.-the program with dynamic programming solution to the classic knapsack problem, although its efficiency and branch and bound over, there is still a certain gap, but its simplicity is incomparab
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0—1背包问题的五种解法
1贪心法
2动态规划
3回溯
4分支限界
5遗传算法-0-1 knapsack problem greedy algorithm five Solution 1 2 3 back in 4 dynamic programming genetic algorithm branch and bound 5
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经典的背包问题用分支限界法实现的JAVA代码-Classical knapsack problem using branch and bound method of the JAVA code
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0/1背包问题的优先队列式分支限界算法程序-0/1 knapsack problem the priority queue-type branch and bound algorithm procedure
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01背包问题，用lc分支限界方法，做的ppt-01 knapsack problem, using lc branch and bound method, do ppt
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这是一个用分支限界法实线01背包问题的说明文档，包含代码-This is a branch and bound method with solid line 01 knapsack problem of documentation, including code
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背包问题分枝界限算法的源代码 其中包括背包容量、下限、剩余容量、当前价值之和
等-Branch-and-bound algorithm for knapsack problem of the source code including backpack capacity, the lower limit, the remaining capacity, the current value and so on
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这是传统智能优化背包问题用VC++ 6.0的实现，是对背包问题分支限界的可视化算法实现-This is a traditional intelligent optimization knapsack problem VC++ 6.0 with the realization of knapsack problem is the visualization of branch and bound algorithm
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用蛮力法，回溯法，分支限界法求解背包问题-With the brute force method, backtracking, branch and bound method for solving knapsack problem
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0-1背包问题是一个经典的算法问题，有多种解法，这里用分支定界法求解。-0-1 knapsack problem is a classical algorithm for the problem, there are several solution here solved with branch and bound method.
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01背包问题的优先队列式分支限界算法程序实现-01 knapsack problem with priority queues to achieve branch and bound algorithm program
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实现0-1背包问题的优先队列分支限界算法
FIFO 分支限界算法
递归法 回溯法 动态规划算法-0-1 knapsack problem to achieve the priority queue FIFO branch and bound algorithms branch and bound backtracking algorithm recursion dynamic programming algorithm
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蛮力、动态规划、回溯、分支限界四种算法求解0/1背包问题-Four algorithms（brute force, dynamic programming, backtracking, branch and bound ） to solve 0/1 knapsack problem
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这是一个关于0-1背包问题算法的编程实现，包括了动态规划、分支界限、回溯、贪心算法-This is a 0-1 Knapsack Problem programming, including dynamic programming, branch and bound, backtracking, greedy algorithm
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回溯法、分支限界法的原理，并能够按其原理编程实现解决0-1背包问题，以加深对回溯法、分支限界法的理解。 -Backtracking, branch and bound method principle, and can according to the principle of programming to realize solving knapsack problem, in order to deepen our understanding of the backtracking, bra
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用java实现的01背包问题的有分支限界的回溯算法，注释非常详细，是我作业的一部分。伪代码可以参考《计算机算法与数据结构》这本书-Using java to achieve 01 knapsack problem branch-and-bound backtracking algorithm and very detailed notes, is part of my job. The pseudo-code can refer to this book of computer algorith
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A branch and bound algorithm for the 0-1 knapsack problem.
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本次实验选择0-1背包问题作为题目，通过使用动态规划、回溯法和分支定界法等算法来求解该问题，从而进一步的了解各种算法的原理、思路及其本质，深化对算法的了解，锻炼自己对各种算法的分析和使用，熟悉软件底层算法和界面编程。-The 0-1 knapsack problem was chosen as the subject, through the use of dynamic programming, backtracking and branch and bound method algorit
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