资源列表
sort
- sort a number decress by qsort
ShiLiangXU
- 徐士良编的一系列程序文档，主要侧重于C语言编译环境-XU Shi-liang compiled a series of program documentation, the main focus on the C language compilation environment
bianchengqiuedezhi
- 简单程序没问题的 简单程序没问题的-Simple program Simple program Simple program
qiufushuzaiqiuhe
- 求负数再求和求 负数再求和求负数再求和-The sum of a negative number then a negative number then the sum of a negative number then the sum of a negative number and then sum
qiuhe
- 求负数再求和求 负数再求和求负数再求和-The sum of a negative number then a negative number then the sum of a negative number then the sum of a negative number and then sum
zhaowanshuqiuhe
- 找完数求和 找完数求和 找完数求和-After looking for the number of summation to find the number of complete end to find the number of sum sum sum to find the number of complete end to find the number of summation
EnhanceWindowList
- 这是一个VC6上的Addin DLL，inpek.com网站上有源码，我对其进行了增强，增加了通过输入自动匹配文件名的功能。可替换VC6的窗口功能。-This is a VC6 the Addin DLL, inpek.com site has a source, I enhanced them, increasing the file name by entering the automatic matching features. VC6 can replace the window fun
mutilthread
- c语言多进程多线程编程的教程，很不错哦,可以学习一下，借此理解操作系统功能。-c multi-process multi-threaded programming language tutorials, very good, oh, you can learn about, to understand the operating system features.
objective-c
- objective-c开发基础教程 请下载 保证资料准确-objective-c development of fundation
AB
- 用字符串输入，然后像做加法一样，对应位相加，然后看是否进位，进位的话下一位加一，用电脑本身的加法是不可能实现20多位的加法的，所以自己写个高精度加法，加几千位甚至上万位都是没问题的。 -I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A+ B.
Code
- Ethernet帧结构解析程序 程序为命令行程序-Procedure for Ethernet Frame Structure for the command-line program
Checksum
- 校验和的计算过程主要分位三个步骤：数据文件的输入，校验和的计算和校验结果的输出。输入数据可能是以字符形式存储的 ，而校验和的计算则要采用数据形式，所以在从文件读取数据时，都要进行字符到数据的相互转换. 使用C＋＋编程时直接使用16进制的方式打开输入文件。待校验的数据按16位位一个单位相加，采用端循环进位，最后对所得16位的数据取反码。因为待校验的数据时以字节方式分隔的 ，所以为了方便，将16位的数据分成高8位和 低8位处理。-Checksum calculation process is div