资源列表
WorkerConsumer
- 制作一个生产者和消费者模型的程序。 一个线程每3秒产生一个4字母长的随机单词作为生产者 一个线程作为消费者,将得到的4字母长的单词记入到一个单词文件中。
PANEL2
- PANELS开发基于DOS环境下用户界面2 PANELS开发基于DOS环境下用户界面 2
delphi
- 实现基本的增、删、改、查等功能,希望对你们有所帮助,谢谢!-By the realization of the basic, delete, change, search and other functions, and they hope to help you, thank you!
volt
- Program in C (CCS to compiler) for the PIC16F84. It is a voltmeter 0 to +5 volts that dispaly the reading in a screen LCD-Program in C (CCS to compiler) for the PIC16F84. It is a voltmeter 0 to+5 volts that dispaly the reading in a screen LCD
RSA
- RSA 原理: 选取两个不同的大素数p、q,并计算N=p*q 选取小素数d,并计算e,使d*e (p-1)(q-1)=1 -RSA works: select two different large prime numbers p, q, and compute N = p* q Select the small prime d, and calculate the e, so d* e (p-1) (q-1) = 1
xiaoganraofa
- 基于电力系统小干扰法 电力系统静态稳定性判断系统是否稳定 -Based on power system small signal method The power system static stability to determine whether a system is stable
Water-level-indicator
- Assembly language code for water level indicator using Micro-controller 8051
rect_array
- 矩形阵仿真,可以得到结果,思路清晰,方便学习,对初学者有很大的帮助-rectangle arry simulation can get the result.it can help the new student to learn it easily
bisect
- matlab的源代码 二分法解方程 matlab程序-matlab source code for solving equations matlab program dichotomy
test_solution
- 解三对角线方程数值解法,在c++环境中使用类轻松实现 -Solution Numerical Solution of tridiagonal equations
Tequurarh
- 开发具有如下函数原型的递归与非递归两种函数equ,负责判断数组a与b的前n个元素值是否按下标对应完全相同,是则返回true,否则返回false。并编制主函数对它们进行调用,以验证其正确性。bool equ(int a[], int b[], int n) 提示:递归函数中可按如下方式来分解并处理问题,先判断最后一个元素是否相同,不同则返false;相同则看n是否等于1,是则返回true,否则进 -The development has the following function prot
panduanshifousushu
- 从键盘输入一个大于3的整数,调用函数fun判断其是否素数,然后在main函数中输出相应的结论信息。-Keyboard input an integer greater than 3, calling function fun to judge whether a prime number, then output information corresponding conclusions in the main function.
