资源列表
1
- R={ r1,r2,… ,rn }是要进行排列的n 个元素。其中元素r1,r2,… ,rn可能相同。试设计一个算法，列出R的所有不同排列。 编程任务：给定n 以及待排列的n 个元素。计算出这n 个元素的所有不同排列。-Sample Input 4 aacc Sample Output aacc acac acca caac caca ccaa 6
Cpp2
- 对以链式存储结构存储的线性表，进行操作运算。要求用菜单选择操作方式完成下列功能。 建立单链表（尾插入，带头结点） 有序链表插入 逆置单链表 两链表合并并排序 算法输入：操作要求、结点信息（可取整型）。 算法输出：操作结果。-Store chain in the structure of the linear form storage, computing operation. Menu to select the requested operation with the
HookKey
- windows xp 下屏蔽系统热键(TAB,左右win皱键等)，delphi 7 + windows xp sp3 下调试通过-under the shield system, windows xp hotkey (TAB, wrinkles around win key, etc.), delphi 7+ windows xp sp3 to debug through the
yuanmab
- 给定一幅raw格式的影像，将它变成一幅bmp图像-change a raw picture to a bmp picture
FSK
- fsk调制解调 改变参数 统计误码率并进行比较-fsk modem to change parameters and compare the bit error rate statistics
romatestart
- 局域网远程唤醒某台电脑的操作程序段，需要发送一个包到某个MAC地址，然后进行唤醒操作。-LAN remote wake-up operation of a computer program segment, needs to send a packet to a MAC address, and then wake-up operation.
chuyen-so-thanh-chu
- convert number to string
w4_zj_1
- 4发空时分组码的编解码和 1收 合并方式-4 rounds of space-time block code encoding and decoding, and one received a consolidated basis
The-inverse-expression-of-Poland
- POJ经典难题——逆波兰表达式VC++解答，附详细代码注释，初学必备-POJ classic problem- the Reverse Polish expression VC++ of answers, with detailed code comments, beginner must
jionDomain
- 将计算机加入域，config.cfg 为配置文件。-Join the computer to a domain, config.cfg configuration file.
sniffer
- linux下c++实现基于libcap的网络嗅探-linux under c++-based network sniffer libcap
envelope
- 对数据信号进行希尔伯特包络 低通滤波包络（需要输入信号数据与采样频率）。(The Hilbert envelope low-pass filtering envelope is used for the data signal (the input signal data and the sampling frequency).)