资源列表
mazemm
- 用栈实现迷宫算法，四个方向寻求出路，四周加边，寻求路径-with Stack achieve maze algorithm, four direction to seek a way out, surrounded bordered seek path
yuesefu1
- new_code( ) 操作结果：构造空链表，若成功就初始化每个人的相关信息 delete_code( ) 初始条件：线性链表存在 操作结果：释放指向出列的人的结点，并重新报数 -new_code () : List structure space, If successful on each of the initialization information delete_code () initial conditions : There linear chain
zhongfuyangjiao
- 五元十字阵中方向的距离定位精度的仿真计算-location of five-element crose array
1
- 2006年全国大学生数学建模参赛程序 第三题（1）-2006 Mathematical Contest in Modeling procedure title entries (1)
vc
- vc代码，用于添回快捷菜单 绘制一个白色矩形背景 可点击任意位置移动的窗体. -vc code for Tim back to the shortcut menu, draw a white rectangle background can click anywhere on the mobile form.
SIS_PSO
- 具备求解大规模复杂函数问题的粒子群优化算法源程序-a PSO algorithm that can solve large scale complex problem.
chengxugaizheng
- 对于初学者易错之处进行点出,方便初学者学习.-Place for beginners prone to point out, easy for beginners to learn.
xiaoxueshengshuxuelianxi
- 随机出10道题（加法、减法、乘法、除法），由学生解答，10道完成后给出成绩及评语。要求加法、减法、乘法、除法各设计一个函数。参数为两个数据，返回解答结果（对为1，错为0）。-Random out of 10 questions (addition, subtraction, multiplication, division), by students to answer, given after completion of 10 grades and comments. Requires add
code-p-value-csharp
- z distribution in Csharp
Binary-decimal-conversion
- 十进制转换二进制 C++实现 仅供参考 -Binary decimal conversion
overloading
- 此代码实现的是C++中的简单的运算符重载问题。-This code is C++ The simple problem of operator overloading.
chepaijiaozheng
- randon 变换进行车牌矫正，通过randon变换获取倾斜角度，根据倾斜角度进行倾斜矫正。-Radon transformation for license plate correction, through the radon transformation to obtain the tilt angle, according to the tilt angle tilt correction.