资源列表
Freescale
- 飞思卡尔智能车大赛获奖车全部程序 飞思卡尔单片机智能循迹小车程序-Freescale' s Smart Car Contest Freescale microcontroller smart cars all the procedures car tracking program
modbusRTU_C51_RS485
- modbus RTU 的C51程序 单片机89S52 通信波特率 9600 8位数据 1位停止位 偶校验 485通位接口 单片机控制板地址 localAddr(变量) 通信可设置数据的地址: 字地址 0 - 255 (只取16位的低8位) 位地址 0 - 255 (只取16位的低8位)-modbus RTU' s C51 program microcontroller 89S52 Communication baud rate 96008 bits of d
MAX1241
- 12位模数转换 ADC MAX1241 C驱动-12-bit analog-digital conversion ADC MAX1241 C drive
UCGUI390a
- ucGUI version3.90的全部源程序代码,以及应用实例,例如,画点,线等各种相关程序。-ucGUI version3.90 all the source code, as well as application examples, such as painting, points, lines and other related procedures.
Key_p1.3
- 用msp430g2553设计的键盘中断程序-With msp430g2553 designed keyboard interrupt program
ARM_Architecture_Reference_Manual
- ARM体系结构手册,包含详细的指令集介绍。-ARM architecture manual, contains a detailed descr iption of the instruction set.
SDcardchinese
- sd卡的接口说明规范,中文翻译的。希望对想要开发SD的朋友有帮助。-sd card interface descr iption norms, the Chinese translation. Want to want to develop friends SD helpful.
FPGA_VHDL_code
- FPGA学习非常珍贵的资料,包括USB、UART、I2C、Ethernet、VGA、CAN等总线的VHDL实现,可以直接应用于实际项目中。需要的请下载。 -FPGA to learn very valuable information, including USB, UART, I2C, Ethernet, VGA, CAN bus, such as VHDL to achieve, can be directly applied to actual projects. Need to do
AT89s52_motor
- 以AT89S52单片机为核心,利用细分技术控制步进电机实现平稳、精确移动-AT89S52 microcontroller to the core, stepper motor control using subdivision smooth, precise movement
samaum-LA40A550-edid
- Samsung 500 series LCD-TV Edid and silicon-image Edid_Editor-Samsung 500 series LCD-TV Edidand silicon-image Edid_Editor
adc
- 用verilog实现TLC549——AD采集实验,采集完的数送给数码管显示-TLC549- AD Acquisition experimental collection finished with verilog number sent to the digital tube display
lcm18b20(my)
- STC12C5410AD单片机对18B20温度的读取,本单片机是1T单片机,里面包含各种演示程序,解决在1T单片机时序不对的问题-STC12C5410AD microcontroller reads the temperature of 18B20, the microcontroller is a microcomputer 1T, which contains a variety of demonstration program, timing does not resolve the is
