资源列表
CalculatorPl
- 实现一个简单计算器，模拟windows自带计算器实现-achieve a simple calculator, simulated windows, bringing their calculators to achieve
syyxcf3D
- fdtd（时域有限差分）的3维仿真程序，用C语言编写，尚未添加PML吸收边界条件。-fdtd (FDTD) of the three-dimensional simulation program, the C language, PML yet to add absorbing boundary conditions.
WondfulCal
- 一个用于多种功能计算需要的计算程序,一个用于多种功能计算需要的计算程序一个用于多种功能计算需要的计算程序-a variety of functions for the calculation of the calculation procedures, a variety of functions for the calculation of a program used for a variety of functions necessary calculation program
NumericalComputingwithMATLAB
- matlab数值计算的很多例程,包括了很多经典的算法,有配套的书,可以结合起来研读,值得研究,很多代码值得直接使用.-Matlab numerical calculation of many routines, including a number of classic algorithms, a matching, can be combined to read, it is worth studying, many worthy code used directly.
GaussMat
- 完全自编Gauss消去法矩阵方程求解程序，各子函数独立小巧，可读性强，矩阵维数可自定义，适用于复杂的线型代数齐次、非齐次方程的求解 -completely self Gauss elimination matrix equation procedures, the independent Functions compact, reader-friendly, Matrix dimension can be self-definition, applicable to complex linear
math_c_code
- 完整的科学计算源代码。 对大家学习和理解数值分析很有帮助。 做适当的修改就可以完成你的分析计算项目。-integrity of the scientific computing source. Members of the study and understanding of numerical analysis helpful. Appropriate changes can be completed your analysis projects.
4mult
- 可用的4位乘法器，用VHDL在FPGA中实现-available four multipliers, FPGA VHDL in achieving
1800Decorations
- 该源码是一个问题的解决方法。问题是给你个长为L的串，串中可以出现n种字符，还给出m个子串，求有多少个长为n的只由这些字串组成的串。输入例子：4 5 6 ABB BCA BCD CAB CDD DDA 结果为2.而5 4 5 E D C B A的结果为625-source of the problem is a solution. The problem is that you have the head of the L series, the series can occur n ch
1500PrePosterous
- 此程序给出一个算法，用于计算当已知一个m叉查找树的先序和后序遍历序列后，存在多少种中序遍历可能。输入格式为m s1 s2，其中m表示m叉树，例子 2 abc cba 结果为4 2 abc bca 结果为1 10 abc bca 结果为45 13 abejkcfghid jkebfghicda 结果为207352860-this procedure is an algorithm, When used in the calculation of a known m Binary S
pctools
- 一个修改二进制文件的小程序,不过在打开大于1M的文件时耗时较长-a binary file to amend the procedures for small, but larger than 1M in opening the documents time-consuming
huolangdan
- 问题：货郎担问题 实现方法：枚举，回溯，动态规划，分支界限法 -: traveling salesman problem Method : Enumeration, backtracking, dynamic programming, branch and bound
useful_formula
- 一些有用的数学公式-some useful mathematical formula !!!!!!!!!!!!!!!!!!!!!!!!!!!