资源列表
Sort
- 数据结构，排序，已经经过编译，可以运行，希望对大家有帮助-Data structures, sorting, have been compiled, you can run, we hope to
guanjianlujin
- 用MFC做的数据结构中的关键路径求解，记得首先必须创建一个AOE网-Solving the critical path of the data structure of the MFC to do, remember that you must first create an AOE network
BinarySortTree
- 数据结构，二叉排序树，已经进行编译，并成功运行，希望对大家有所帮助-Data structure, binary sort tree, compile and run successfully, we hope to help
guanjianlujing-cmd
- 关键路径数据结构课程设计的控制台程序，创建网的时候请注意空格字符-Critical path data structure courses designed console application to create a network Please note that the space character
Search
- 数据结构，静态查找，已经过编译，并成功运行，希望对大家有帮助-Data structures, static lookup, has been compiled and run successfully, we hope to
binary-tree
- 分别以先序和中序遍历序列，后序和中序遍历序列构造一棵二叉树 要求以括号表示法输出该二叉树-Preorder and inorder traversal sequence after sequence, and the traversal sequence construct a binary tree the brackets indicate the method outputs the binary tree
LinkQueue
- 数据结构，链队栈，已经经过编译，并成功运行，希望对大家有帮助-Data structure, the chain teams stack, has been compiled and run successfully, we hope to
Josephus
- 编写程序，模拟约瑟夫环（josephus）问题： n个人（编号为1，2，3，……，n (n>0) ）按顺时针方向围坐一圈，每人持有一个正整数密码。开始时任意给出两个值：一个为首先报数的人的编号i (0<i<=n)，另一个为起始报数上限值m。接着从编号为i的人开始按顺时针方向自1起顺序报数，报到m时停止报数，且报到m的人出列，并将他的密码作为新的m值，从他在顺时针方向上的下一个人起重新自1报数，……，如此下去，直到所有人全部出列为止。要求设计一个程序模拟此过程，给出出列人的编号序
Hexadecimal-conversion
- 进制间的转换，2进制，8进制，10进制，16进制间的转换-Convert between hexadecimal, binary, octal, decimal, hexadecimal conversion
Broken-Necklace.tar
- usaco上面的习题，我自己写的代码，所有数据可以AC过的。-usaco above exercises, write my own code, all data can be AC off.
cpp.tar
- 这是usaco上面的全部习题代码，足够ACMer们研习一阵了，全部代码都AC过。-This is above all exercises usaco code, enough ACMer who study a while, all the code over to AC.
VCPP-genetic-reconfiguration
- 基于VC++的电力系统遗传算法重构实现. 用于减少系统损耗的重构,包含了潮流功能-Power genetic algorithm-based VC++ reconstruction. Used to reduce the loss of the reconstruction of the system, including the trend