资源列表
a
- 贪心法求0/1背包 已知背包的容量和物品的个数和重量价值 -The greedy algorithm to find 0/1 knapsack
Graph
- 邻接矩阵的建立，赋值和输出所建立 的矩阵-The establishment of the adjacency matrix, assignment and the output of a matrix
A-star
- 对于空地左键单击后会产生障碍，对障碍左键单击会消除障碍，对于起点，两次左键盘单击会消除起点，如果不存在起点，单击右键会产生起点，如果存在起点不存在终点，单击右键会产生终点，如果既存在起点又存在终点，单击右键会消除终点，点击开始寻路回画出路径-For space left click on to generate barrier of the obstacles left click on will eliminate obstacles, for starting point, two left
huffman
- 此源代码为huffman代码，用来解决huffman树的问题-this code is huffman s code .To solve the problem of the huffman tree
3-2010111119
- 对输入的矩阵，输出其自反闭包、对称闭包，并利用Warshall算法实现其传递闭包-The matrix of input, output since the the closure, symmetry closure, and use Warshall algorithm to realize its relay closure
paixu
- 希尔排序，快速排序，简单选择排序，冒泡排序，堆排序，插入排序，归并排序-Hill sorting, quick sort, simple choice sorting, bubble sort, heap sort, insertion sort, merge sort
linjiejuzhen
- 对任意给定的图（顶点数不小于20，边数不少于30，图的类型可以是有向图、无向图、有向网、无向网），能够输入图的顶点和边（或弧）的信息，并存储到相应存储结构（邻接矩阵、邻接表、十字链表、邻接多重表，任选其中两种类型）-For any given figure (vertices not less than 20, the side for not less than 30, graph the type can be directed graph, no to figure, was the ne
Business-statistics
- 营业统计，acm比赛题目。用C++编写，能够通过编译。-Business statistics, acm title game. Written in c++, able to compile.
Tree
- 创建二叉树，实现二叉树的前序遍历，中序遍历，后续遍历，层次遍历等功能！-Create a binary tree, realize the binary tree of the preface of the traverse, in order to traverse, the follow-up to traverse, the function such as level traversal!
tinylinker
- 小型链接器，系统级编程课程设计，题目要求编写两个函数-A small linker, system-level programming course design
2
- fft，最优二叉树和矩阵链乘的c++实现，并进行了对比，用来计算时间复杂度-sdfaf dsasd fafhq ae sdga badfgt g agaq s asgasga
c
- 小妹上传的是大学学习数据结构所做的实验题目，主要涉及到链表等相关部分。-what I have upload is about the program in data structure experiment.please accept it!